JEE ADVANCED 2019 RESULT & COUNSELLING
NATIONAL LEVEL ONLINE TEST
JEE Advanced 2019 Result has been declared on June 14, 2019 at jeeadv.ac.in by IIT Roorkee. Candidates have to enter their Registration Number and Date of Birth to view their JEE Advanced Rank and Score.
Out of 161319 students who appeared in JEE Advanced 2019, 38705 students including 5356 females qualified the exam. Scoring 346 marks out of 372, Gupta Kartikey Chandresh from Maharashtra has topped IIT JEE Advanced 2019. Also, he had secured an All India Rank 17 with 100 Percentile in JEE Main 2019. Shabnam Sahay is topper among female candidates obtaining AIR 10 with 308 marks. Download Official PDF
Read on to know more about JEE Advanced Result, Important Dates, Cutoffs and Participating Colleges.
Following are the highlights of JEE Advanced Result 2019:
|Total number of Appeared Candidates||1,61,319|
|Total number of Qualified Candidates||38705|
|Total number of Qualified Boys||33349|
|Total number of Qualified Girls||5356|
|Total number of Qualified General Candidates||15566|
|Total number of Qualified General EWS Candidates||3636|
|Total number of Qualified OBC Candidates||7651|
|Total number of Qualified SC Candidates||8758|
|Total number of Qualified ST Candidates||3094|
|IIT Bombay||GUPTA KARTIKEY CHANDRESH (CRL 1)|
|IIT Delhi||HIMANSHU GAURAV SINGH (CRL 2)|
|IIT Guwahati||PRADIPTA PARAG BORA (CRL 28)|
|IIT Kanpur||DHRUV ARORA (CRL 24)|
|IIT Kharagpur||GUDIPATY ANIKET (CRL 29)|
|IIT Hyderabad||GILLELLA AKASH REDDY (CRL 4)|
|IIT Roorkee||JAYESH SINGLA (CRL 17)|
|OPEN (CRL)||1||GUPTA KARTIKEY CHANDRESH|
|OPEN (CRL)||2||HIMANSHU GAURAV SINGH|
|OPEN (CRL)||3||ARCHIT BUBNA|
|GEN-EWS||1||D CHANDRASEKHARA S S HETHAHAVYA|
|OBC-NCL||1||HIMANSHU GAURAV SINGH|
|OBC-NCL-PwD||1||VEDANT DEEPAK BORKUTE|
JEE Advanced Result 2019 is declared on June 14, 2019. After the declaration of JEE Advanced Result 2019, the process for AAT 2019 will begin on June 14. Refer to the below table to learn about all important JEE Advanced Result Dates:
|Declaration of JEE Advanced Result 2019||June 14, 2019|
|Online Registration for Architecture Aptitude Test (AAT)||June 14 to 15, 2019|
|Architecture Aptitude Test Date||June 17, 2019|
|Declaration of AAT 2019 Result||June 21, 2019|
|JoSSA Counselling||June 22– July 15, 2019|
Candidates need to follow the below procedure in order to check JEE Advanced Result 2019:
Following are the particulars indicated JEE Advanced 2019 Result:
Only candidates who have appeared for both the papers of JEE Advanced, will be considered for Common Rank List (CRL). Marks obtained in Paper 1 and Paper 2 will be taken while the rank is calculated by the concerned authorities. The example is mentioned below:
Marks obtained in Physics = Marks obtained in Paper 1 (Physics) + Marks obtained in Paper 2 (Physics)
Similar method will be used for calculating total marks for Mathematics and Chemistry. The aggregate marks for JEE Advanced 2019 will be calculated using the following formula:
Aggregate Marks/Scores obtained in JEE Advanced = Aggregate marks in (Physics + Mathematics + Chemistry)
The rank list of JEE Advanced 2019 will be prepared based on the aggregate marks obtained by the candidates in the entrance examination. Only candidates who score the minimum prescribed marks in each subject and in aggregate will be included in the rank list.
JEE Advanced final answer keys have been released along with result declaration on June 14, 2019. The provisional answer keys were available on the online portal since June 4, 2019 at jeeadv.ac.in. IIT Roorkee also allowed candidates to send feedback on answer keys through the portal. With the announcement of JEE Advanced result, the final frozen answer keys and minimum marks for inclusion in the rank list have also been published at the official portal.
JEE Advanced cut off is the score of the candidate with the lowest rank who will be accepted by IITs for admission. IITs also prefer Minimum Qualifying Marks for Ranking (MQMR) which is the minimum scores for JEE Advanced, required to be eligible for including in JEE Advanced Common Rank List.
The cut off marks for PwD candidates will be the same as the lowest of the cut off marks for GEN, OBC-NCL, SC and ST categories.
The minimum percentage of marks prescribed for inclusion in the rank list are elucidated in the following table:
|Rank list as per the Categories||Minimum percentage of marks in each subject||Minimum percentage of aggregate marks|
|Common rank list (CRL)||10.0||35.0|
|OBC-NCL rank list||9.0||31.5|
|SC rank list||5.0||17.5|
|ST rank list||5.0||17.5|
|Common-PwD rank list (CRL-PwD)||5.0||17.5|
|OBC-NCL-PwD rank list||5.0||17.5|
|SC-PwD rank list||5.0||17.5|
|ST-PwD rank list||5.0||17.5|
|Preparatory course rank list||2.5||8.75|
JoSSA will be carrying out the counselling procedure for selection of candidates into the IITs and other affiliated institutes. The candidates will be allotted the college and branch as per their choice but in accordance with their AIR.
For that the candidates will have to wait for the declaration of the AIR and the counselling procedure will commence in the third week of June 2019. JEE Advanced Counselling is centrally managed computerized process and candidates need to report directly to allotted colleges.
Eligibility Criteria for JEE Advanced Counselling
Read About JoSAA Counselling
Post declaration of JEE Advanced Result, desired candidates must register for Architecture Aptitude Test 2019 at jeeadv.ac.in. Only candidates who have qualified in JEE Advanced can register for AAT.
*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College
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