NCERT Solutions for Class 12 Maths Chapter 4 Determinants Exercise 4.2

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CBSE CLASS XII Related Questions

  • 1.
    For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

      • local maximum value is 2
      • local minimum value is \( -2 \)
      • local maximum value is \( -2 \)
      • local minimum value \( < \) local maximum value

    • 2.

      If \[ B(\operatorname{adj} B)= \begin{bmatrix} \frac{1}{3} & 0 & 0\\ 0 & \frac{1}{3} & 0\\ 0 & 0 & \frac{1}{3} \end{bmatrix}, \] then the value of \[ \det(B^{-1}) \] is: 

        • \(\frac{1}{3}\)
        • \(\frac{1}{9}\)
        • \(3\)
        • \(9\)

      • 3.

        Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not. 


          • 4.
            The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:

              • \( e^{-3} \)
              • \( -1 \)
              • \( 1 \)
              • \( -e^3 \)

            • 5.
              Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]


                • 6.

                  For two vectors \(\vec{a}\) and \(\vec{b}\):  

                  Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

                    • Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
                    • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                    • Assertion (A) is true, but Reason (R) is false.
                    • Assertion (A) is false, but Reason (R) is true.
                  CBSE CLASS XII Previous Year Papers

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