NCERT Solutions for Class 12 Maths Chapter 4 Determinants Exercise 4.5

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NCERT Solutions for Class 12 Maths Chapter 4 Determinants Exercise 4.5 is provided in this article with step by step explanation. Chapter 4 Exercise 4.5 has questions covering concepts of determinants such as how to find the inverse of a matrix using adjoint. The questions make use of many theorems to deal with the adjoint and Inverse of a Matrix.

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Class 12 Maths Chapter 4 Determinants Topics:

Inverse Laplace Transform	Determinant Formula	Applications of determinants and matrices
Properties of Determinants	Determinants and Matrices	Elementary Matrix Operations
Difference between rows and columns	Jacobian Method	Consistent and inconsistent system of equations
Consistent System of Linear Equations	Minors and Cofactors	Non-singular matrix

CBSE Class 12 Mathematics Study Guides:

Math MCQs	Math Study Notes	Math Formula
Algebra	Geometry	Probability and Statistics
Calculus	Arithmetic	NCERT Solutions for Class 12 Maths
Mensuration	Trigonometry	Difference between in Maths

CBSE CLASS XII Related Questions

1.
A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length.
2.
An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.
Based on the above information, answer the following questions :
3.
Find:

If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).
- \(0\)
- \(-2\)
- \(-1\)
- \(2\)
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4.
Find:

The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:
- \(-\frac{\pi}{2}\)
- \(-\frac{\pi}{4}\)
- \(\frac{\pi}{4}\)
- \(\frac{\pi}{2}\)
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5.
Find:
Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).
- \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
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6.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).
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