NCERT Solutions for Class 7 Mathematics Chapter 11: Perimeter and Area

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NCERT Solutions for Class 7 Mathematics Chapter 11 Perimeter and Area is provided in this article. Two-dimensional forms have two key properties: area and perimeter. The perimeter of a form is defined by the distance between its boundary and the area occupied by it. Some of the important topics in Perimeter and Area chapter includes:

Rectangle
Difference Between Area and Perimeter
Area of Square Using Diagonal
Perimeter and Area Formula
Perimeter of Triangle
Square Footage Formula

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 11 pdf

NCERT Solutions for Class 7 Mathematics Chapter 11

NCERT Solutions for Class 7 Mathematics Chapter 11 Perimeter and Area is given below.

NCERT Solutions for Class 7 Mathematics

Area: It is the two-dimensional space occupied within the boundaries of a geometrical figure.

Perimeter: It is the length of the boundary of a two-dimensional geometrical figure.

Example 1: Find the area of a square of side 5 cm.

Ans. We know that,

Area of square = a x a

Area = 5 x 5

Area of square = 25 sq.cm

Example 2: Find the perimeter of square of side 10 cm.

Ans. We know that,

Perimeter of square = 4a

Perimeter = 4 x 5

Perimeter = 20 sq.cm

NCERT Solutions for Class 7 Maths Chapter 11 Exercises

NCERT Solutions for Class 7 Maths Chapter 11 Area and Perimeter Exercises are given below.

Read More:

Square Formula	Area Formulas
Area of Shapes	Perimeter of Square Formula

Class 7 Maths Study Guides:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals
- \(2.5\) cm
- \(10.5\) cm
- \(3.5\) cm
- \(\frac{14}{3}\) cm
View Solution
2.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- \( 130^\circ \)
- \( 50^\circ \)
- \( 120^\circ \)
- \( 90^\circ \)
View Solution
3.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
View Solution
4.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?
- 144
- 2
- 420
- 272
View Solution
5.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)
View Solution
6.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution

View All

Mathematics Preparation Guides

Area of a Triangle: Formula, Types & Examples

Isosceles Triangle Theorems: Proof and Sample Questions

How to Calculate Percentage: Formula, Basic Tricks, Solved Examples

Difference Between Area and Perimeter: Definitions & Formulas

Area of Square Using Diagonal: Formula, Relation & Derivation

Additive Inverse: Formula, Properties, Fraction & Complex Numbers

BODMAS Rule: Definition, Rules and Sample Questions

Isosceles Right Triangle: Formulas, Pythagoras Theorem and Area

Unitary Method: Steps, Types of Unitary Method, Solved Examples

Triangle Theorems: Properties, Types & Similarity Theorems

Percentage: Formula, Conversions and Examples

Area of Isosceles Triangle: Formula, Properties & Examples

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Perimeter of a Trapezoid Formula: Perimeter, Quadrilateral, Polygons

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Percentage Formula: How to Calculate Percentage?

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NCERT Solutions for Class 7 Mathematics Chapter 1: Integers

NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for Class 7 Mathematics Chapter 5: Lines and Angles

NCERT Solutions for Class 7 Mathematics Chapter 9: Rational Numbers

NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

NCERT Solutions For Class 7 Mathematics Chapter 4: Simple Equations

NCERT Solutions for Class 7 Mathematics Chapter 8: Comparing Quantities

NCERT Solutions for Class 7 Mathematics Chapter 11: Perimeter and Area

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 11 pdf

NCERT Solutions for Class 7 Mathematics Chapter 11

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 11 Exercises

CBSE X Related Questions

1.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

2.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

3.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

4.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

5.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

6.
The HCF of 960 and 432 is :

Comments

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NCERT Solutions for Class 7 Mathematics Chapter 11: Perimeter and Area

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 11 pdf

NCERT Solutions for Class 7 Mathematics Chapter 11

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 11 Exercises

CBSE X Related Questions

1.In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

2.In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

3.In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

4.There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

5.Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

6.The HCF of 960 and 432 is :

Comments

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1.
In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

2.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

3.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

4.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

5.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

6.
The HCF of 960 and 432 is :