NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclid's Geometry Exercise 5.2 Solutions are based on Euclid’s fifth postulate.

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Read More: NCERT Solutions For Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

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CBSE X Related Questions

  • 1.
    It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

      • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
      • \(\frac{AB}{ED} = \frac{AC}{EF}\)
      • \(\angle A = \angle D, \angle C = \angle F\)
      • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

    • 2.
      In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

        • $6$
        • $4$
        • $\pm 4$
        • $3$

      • 3.
        In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

          • $55^\circ$
          • $20^\circ$
          • $35^\circ$
          • $70^\circ$

        • 4.
          If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

            • \(4 \text{ cm}\)
            • \(4\sqrt{2} \text{ cm}\)
            • \(8 \text{ cm}\)
            • \(2\sqrt{2} \text{ cm}\)

          • 5.
            If for a data, median is 5 and mode is 4, then mean is equal to :

              • 7
              • 11
              • \(\frac{11}{2}\)
              • \(\frac{14}{3}\)

            • 6.
              If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

                • \(\frac{7}{2}\)
                • \(\frac{6}{7}\)
                • \(\frac{-7}{6}\)
                • \(\frac{7}{6}\)

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