NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclid's Geometry Exercise 5.1 Solutions are based on the introductions of Euclid’s geometry, axioms and postulates.

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Check out NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.1 Solutions

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

Also check other Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclid's Geometry Exercise 5.2 Solutions

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Chapter Related Topics
Introduction to Euclid’s Geometry - MCQs	Euclid’s Division Lemma

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CBSE X Related Questions

1.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is
- 34
- 43
- 38.5
- 41.5
View Solution
2.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are
- $(x + 2), (x - 5)$
- $(x + 5), (x - 2)$
- $(x + 1), (x - 5)$
- $(x - 1), (x + 2)$
View Solution
3.
For an acute angle $\theta$, if $\sin \theta = \frac{1}{9}$, then value of $\frac{9 \csc \theta + 1}{9 \csc \theta - 1}$ is
- $0$
- $\frac{80}{81}$
- $1$
- $\frac{82}{80}$
View Solution
4.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is
- $6$
- $4$
- $\pm 4$
- $3$
View Solution
5.
Arc $PQ$ subtends an angle $\theta$ at the centre of the circle with radius $6.3 \text{ cm}$. If $\text{Arc } PQ = 11 \text{ cm}$, then the value of $\theta$ is
- $10^{\circ}$
- $60^{\circ}$
- $45^{\circ}$
- $100^{\circ}$
View Solution
6.
It is given that $\triangle ABC \sim \triangle EDF$. Which of the following is not true?
- $\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}$
- $\frac{AB}{ED} = \frac{AC}{EF}$
- $\angle A = \angle D, \angle C = \angle F$
- $\frac{AB + BC}{AC} = \frac{ED + DF}{EF}$
View Solution

View All

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You can also check

NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.1 Solutions

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

CBSE X Related Questions

1.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

2.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

3.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

4.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

5.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

6.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

Similar Mathematics Concepts

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NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.1 Solutions

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

CBSE X Related Questions

1.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

2.The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

3.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

4.In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

5.Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

6.It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

2.
The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

3.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

4.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

5.
Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

6.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?