Nuclear Binding Energy: Curve, Mass Defect, Examples

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Jasmine Grover

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Nuclear Binding Energy can be defined as the energy required that disassembles a nucleus into separate neutrons and protons. Albert Einstein proposed the theory of relativity in the 20th century. The theory states that the mass and energy are inconvertible which means the mass can be converted into energy and vice-versa. This additional dimension to physics was helpful in the resolution of many unsolved problems and provided a platform for many new theories. The existence of Nuclear Binding energy is one of them.

Keyterms: Nuclear Binding Energy, Energy, Nucleus, Neutrons, Protons, Binding Energy, Speed of light, Light


Definition: Nuclear Binding Energy

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A common person rarely considers how much energy it will take to break the log into two but for a physicist, energy plays an extremely important role.The binding energy (B.E.) of the nucleus is the amount of energy necessary to completely break down the nuclei into individual protons and neutrons. The B.E. of the nucleus can be determined using the rest mass.

Nuclear Binding Energy

Nuclear Binding Energy

Mass defect defines the missing mass and Einstein’s equation E = mc2 offers a relation of energy to the missing mass.

Where,

  • E = Energy
  • m = Mass
  • c = Speed of light

The well-known Einstein relationship joins both the terms m and c. The bound system has a lower mass than its separate constituents. When the nucleons are more closely bonded together, the nucleus’ mass is reduced.

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Nuclear Binding Energy: Process

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Assume that the nuclide is being pulled apart. The work done to overcome the nuclear forces that hold the nuclei together is the energy put into the system. The energy applied into the system is defined as the work done to control the nuclear forces that hold the nuclei.

Nuclear Binding Energy

Nuclear Binding Energy

The energy applied into pulling apart the nucleus, its individual neutrons and protons causes the system’s mass to grow. Binding energy (BE) is equal to the work needed for disassembling the nucleus.

In comparison, the mass of the bound system is lesser than the total sum of its parts, which is particularly obvious in the nuclei, where the energies and forces are huge.


Mass Defect

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According to the definition, the binding energy is equal to the input energy. The pieces are at rest when separated. When compared to their glued together state, the total rest mass increases as the energy placed into them increases.

Nuclear Binding Energy: Mass Defect

Nuclear Binding Energy: Mass Defect

Thus, the increased mass is,

Δm = BE/c2

Mass Defect or Mass Difference Derivation

The mass difference or mass defect is the sum of the total mass of the nucleus constituents; the mass of the protons and neutrons is more than the mass of the nucleus.

A nuclide AX contains N neutrons & Z protons therefore the difference in mass will be:

\(\bigtriangleup\)m = (Zmp+ Nmn) − mtot

Thus, BE = (Δm) c2= [(Zmp+ Nmn) − mtot]c2

Where,

mtot = Mass of nuclide AX,

mp = Mass of the proton

& mn = Mass of the neutron

We conventionally use the masses of neutral atoms.

To get atomic mass into the last equation, add Z electrons to mtot. This will further give you m(AX), the atomic mass of nuclide.

Then, add Z electrons to Z protons. This will give you Zm (1H), or Z times a mass of hydrogen atom.

Therefore, the binding energy of a nuclide will be,

AX is BE = {[Zm(1H)+ Nmn]− m(AX)}c2.


Binding Energy Curve

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The binding energy curve graph can be plotted based on per nucleon versus atomic mass and can be represented as follows:

Nuclear Binding Energy Curve

Nuclear Binding Energy Curve

Due to the presence of only one proton in the nucleus the binding energy of hydrogen is zero and therefore there will be no electrostatic repulsion. It is clearly visible from the graph that the binding energy drastically rises till helium and then falls a bit before climbing back up to the iron56. After reaching iron-56, binding energy gently drops towards U-238.

Nuclear Binding Energy Curve

Nuclear Binding Energy Curve

Anything present on the left-side of Fe-56 can be created in the process of nuclear fusion. In this process, the atoms are compressed under extreme temperature and pressure to generate heavy elements.

Similarly, anything present on the right side of Fe-56 can be created in the process in which heavy atoms are broken into lighter elements.


Main Features of Binding Energy Curve

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The binding energy per nucleon is the average energy per nucleon required to separate a nucleus into its constituent nucleons. The main features of the binding energy curve are:

1.) For nuclei with a middle mass number (30bn) is constant and practically independent of the atomic number. The curve has a maximum value of around 8.75 MeV for A = 56 and a value of 7.6 MeV for A = 238.

2.) Both light nuclei (A<30) and heavy nuclei (A>170) have lower binding energy per nucleon.

Nuclear Binding Energy Curve

Nuclear Binding Energy Curve

Based on the above two observations, the following conclusion can be drawn:

  • The force should be attractive and strong enough to provide binding energy of a few MeV per nucleon.
  • As the nuclear force is short-ranged the binding energy’s range of constancy is from 30 < A < 170.

For instance: A heavier nucleus with A = 240 has a lower binding energy per nucleon than a lighter nucleus with A = 120. Therefore, if A = 240 nucleus breaks into two A = 120 nuclei, the nucleons bound more firmly, implying that energy is released in the process.


Things to Remember

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  • Nuclear binding energy is the amount of energy needed to split an atom’s nucleus into its components.
  • Nuclear binding energy is used to find out whether fusion or fission will be a favorable process.
  • The binding energy (B.E.) of the nucleus is the amount of energy necessary to completely break down the nuclei into individual protons and neutrons.
  • When the nucleons are more closely bonded together, the nucleus’ mass is reduced.

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Sample Questions

Ques. What will be the binding energy of the Deuteron if the mass of the deuteron is 1875.61MeV/c2or 3.34359 x 10-27Kg. (5 marks)

Ans: Mass of deuteron mD = 1875.61 MeV/c2 or 3.34359 x 10-27 Kg.

Atomic Mass number of Deuteron; A=2

The atomic number of Deuteron; Z=1

Mass defect is given by Δm = Zmp + (A−Z) mn − mnuc

Here Z = 1 and (A-Z) = 1

mn =939.57MeV/c2

and,mp =938.28 MeV/c2

After substituting the values we get,

Δm = mp + mn– mD

= 938.28 MeV/c2 + 939.57MeV/c2 – 1875.61MeV/c2

=2.24 MeV/c2

Thus, the mass defect is 2.24 MeV/c2.

The binding energy of the Deuteron will be Eb=(Δm)c2

= (2.24 MeV/c2)(c2)

=2.24 MeV

Ques. What is the Binding Energy Formula? (3 marks)

Ans: The binding energy (BE)is defined as the amount of energy needed to divide a nucleus into individual protons and neutrons. In terms of atomic masses, BE is written as;

BE = {[Zm (1H) + Nmn] - m (AX)}c2

Where,

M (1H) = Mass of hydrogen atom

M (AX) = Atomic mass of nuclide

mn = Mass of neutron

Ques. Is Binding Energy positive or negative? (2 marks)

Ans: If the binding energy is positive or zero, the nucleus will separate and escape into space, hence it is negative. The neutrons and protons in a nucleus are held together by a strong nuclear force and have potential energy in them.

Ques. Why is the energy released when there is an increase in Binding Energy? (2 marks)

Ans: When protons and neutrons react to form bonds, the nuclear binding energy is released. The binding energy gives up a substantial amount of energy as the number of nucleons grows.

Ques. Find the nuclear density when the mass of an iron nucleus is 55.85u and A=56? (3 marks)

Ans: mFe= 55.85, u = 9.27 x 10-26 kg

Nuclear density = mass/volume = 9.27 x 10-26/ (4π/3)(1.2 x 10-15)3 x 1/56

= 2.29 x 1017 Kgm-3

Ques. What will be the average binding energy per mole of a U-235 isotope? (5 marks)

Ans: U-235 contains 143 neutrons, 92 protons and has an observed mass of 235.04393 amu.

Md = (mn+mp) − mo

Md = (92(1.00728 amu) + 143(1.00867 amu)) – 235.04393 amu

Md = 1.86564 amu

The mass in Kg will be:

1.86564 amu x 1 kg/6.02214 × 1026 amu

= 3.09797 x 10-27 kg

Now, we will calculate the energy using the formula:

E = mc2

= 3.09797 x 10-27 kg x (2.99792458 x 108 m/s)2

= 2.7843 x 10-10 J

Ques. Calculate the binding energy per nucleon of an 4He (α particle). (5 marks)

Ans: First, we will calculate the total binding energy by using the equation

BE = (Δm)c2

Where,

Δm = mass defect

For 4He, we have Z = N = 2. So, the total binding energy will be

BE = {[2mp + 2mn] − m(4He)}c2

These masses are m(4He) = 4.002602u, mp = 1.007825u, mp = 1.007825u and mn = 1.008665u. Then, BE will be;

BE = (0.030378u)c2

When, 1u = 931.5 MeV/c2, we get

BE = (0.030378) (931.5 MeV/c2)c2

= 28.3 MeV

Since, A = 4, the total binding energy per nucleon will be,

BEN = 7.07 MeV/nucleon

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