Limits and Continuity: Definition, Types and Discontinuity

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Jasmine Grover

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A limit is a number that the function approaches as an independent function's variable approaches a specific value. Another popular topic in calculus is continuity. Examining whether a pen can trace the graph of a function without lifting the pen from the paper is a simple way to test for function continuity. A conceptual definition is almost sufficient for precalculus and calculus, but a technical explanation is required for higher levels. Limits can help you discover a more specific approach of determining continuity.

Read More: Continuity and Differentiability

Key Takeaways: Continuous functionsrate of change, velocity, first-order derivative, second-order derivative, Functions, Number, Limit, Continuous functions, Real function

Also Read: Limit formula


Definition of Continuity

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Many functions have the virtue of being able to trace their graphs with a pencil without removing the pencil off the paper. These are called Continuous functions, a function is continuous at a given point if its graph does not break at that point. In general, a calculus introductory course will provide a clear description of continuity of a real function in terms of the limit's idea. First, a function f with variable x is continuous at the point "a" on the real line if the limit of f(x), as x approaches "a," is equal to the value of f(x) at "a," i.e., f(a).

Continuity can be described mathematically as follows:

If the following three conditions are met, a function is said to be continuous at a given point.

  1. f(a) is defined
  2. lim x→a f(x) exists
  3. limx→a+f(x)=lim x→a f(x)=f(a)

When a graph can be traced without lifting the pen from the sheet, the function is said to be a continuous function. A function, on the other hand, is said to be discontinuous if it contains any gaps in between.

Discover about the Chapter video:

Continuity and Differentiability Detailed Video Explanation:

Also Read: First Order Differential Equation


Types of Discontinuity

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  • Infinite discontinuity: A branch of discontinuity with a vertical asymptote at x = a and f(a) is not defined. Asymptotic Discontinuity is another name for this. A function can't be connected if it has values on both sides of an asymptote, therefore it's discontinuous at the asymptote.
  • Jump discontinuity: A branch of discontinuity in which limx→a+f(x)≠limx→a−f(x), but of the both limits are finite. This is also known as simple discontinuity or continuity of the first kind. 
  • Positive Discontinuity: A branch of discontinuity in which a function has a predefined two-sided limit at x = a, but f(x) is either undefined or not equal to the limit at a. A removable discontinuity is another name for this.

These can be represented graphically as:

Also Read: Integers As Exponents


Definition of Limit

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A function's limit is a number that a function reaches when its independent variable reaches a certain value. The value (say a) to which the function f(x) approaches arbitrarily as the independent variable x approaches arbitrarily a given value "A" denoted as f(x) = A.

If limx→a- f(x) is the expected value of f at x = a given the values of ‘f’ near x to the left of a. This value is referred to as the left-hand limit of ‘f’ at a.

If limx→a+ f(x) is the expected value of f at x = a given the values of ‘f’ near x to the right of a. This value is referred to as the right-hand limit of f(x) at a.

If the right-hand and left-hand limits coincide, then it is referred to as a common value as the limit of f(x) at x = a and denote it by lim x→a f(x).

Also Read: Differentiation and Integration Formula


One sided limit 

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The limit that is entirely determined by the values of a function for an x-value that is slightly higher or less than a given value. A two-sided limit lim x→af(x)lim x→af(x) takes the values of x into consideration that are both larger than and smaller than a. A one-sided limit from the left limx→a−f(x)limx→a−f(x) or from the right limx→a−f(x)limx→a−f(x) takes only values of x that is smaller or bigger than a respectively.

Also Read: Inverse Trigonometric Formulas


Things of Remember

  • When a graph can be traced without lifting the pen from the sheet, the function is said to be a continuous function. A function, on the other hand, is said to be discontinuous if it contains any gaps in between.
  • If limx→k− f(x)limx→k−f(x) is the expected value of f at x = k stated the value of ‘f’ is close by x to the left side of k. The left-hand limit of 'f' at k is used to determine this value.
  • If limx→k+ f(x) is the average value of f at x = k, then the values of 'f' on the right side of k are lim x→k+f(x). The right-hand limit of f(x) at k is used to determine this value.
  • If the right-hand and left-hand limits meet, the common value is called the limit of f(x) at x = k and is denoted by limx→kf(x).
  • The limit of any constant function will always be a constant term limx→yC= C.

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Sample Questions

Ques. Find the value of limx→3 [x(x+2)]. (1 marks)

Ans: limx→3 [x(x+2)] = 3(3+2) = 3 x 5 = 15

Ques. Check the continuity of the function f given by f (x) = 2x + 3 at x = 1. (NCERT) (2 marks)

Ans: As we know that the function is defined at the given point x = 1 and its value is 5. Finding limit of the function at x = 1.

limx→1 f(x) = limx→1 f(2x+3) = 2(1)+3 = 5

limx→1 f(x) = 5 = f(1)

Therefore, f is continuous at x = 1.

Ques. Check the points where the constant function f (x) = k is continuous. (NCERT) (2 marks)

Ans: Let c be any real number.

Then limx→c f(x) = limx→c k = k

Since f(c) = k = limx→c f (x) for any real number c, Thus in this case, the function f is continuous at every real number.

Ques. Compute limx→ −2 (3x2+5x−9) (2 marks)

Ans: Using property 2 to divide the limit in 3 different limits. After that, using property 1 to bring the constants out of the first two. We get,

limx→−2(3x2+5x−9)=limx→−2 (3x2)+limx→−2(5x)−limx→−2(9)=3(−2)2+5(−2)−(9)=3(−2)2+5(−2)−(9) = 12 – 10 – 9 = -7

Ques. Discuss the continuity of sine function. (2 marks)

Ans: lim x→0 sinx=0

It is intuitively clear from the graph of sin x near 0.

Let's observe that f (x) = sin x is defined for every real number. Let c be a real number. Put x = c + h. If x → c we know that h → 0.

Therefore,

limx→c f(x) = lim→x sinx = limh→0 sin(c+h) = lim h→0 [sinc cosh + cosc sinh] = lim h→0 [sinc cosh] + lim h→0 [cosc + sinh] = sinc c + 0 = sin c = f(c)

Thus, limx→c f(x)=f(c) and f is a continuous function.

Ques. Show that the function defined by f(x) = sin (x2) is a continuous function. (2 marks) 

Ans: The function is defined for every real number. The function f may be thought of as a composition g o h of the two functions g and h, where g (x) = sin x and h(x) = x2 . By Theorem 2, we can deduce that f is a continuous function because both g and h are continuous functions.

Ques. Show that the function f defined by f (x) = |1 – x + | x| |, where x is any real number, is a continuous function. (2 marks)

Ans: Let us define g by g (x) = 1 – x + | x| and h by h (x) = | x| for all real x.

Then (h o g) (x) = h (g (x)) = h (1– x + | x|) = | 1– x + | x| | = f (x)

Ques. Examine the continuity of the function f(x) = 2x2 – 1 at x = 3. (2 marks)

Ans: The given function is f(x) = 2x2 – 1

At x=3, f(3)=2(3×3)-1 = 17

limx→3 f(x)= limx→3 2x2 – 1= 2(3×3)-1 = 17

limx→3 f(x) = f(3)

therefore, f is continuous at x=3.

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CBSE CLASS XII Related Questions

  • 1.

    If \[ B(\operatorname{adj} B)= \begin{bmatrix} \frac{1}{3} & 0 & 0\\ 0 & \frac{1}{3} & 0\\ 0 & 0 & \frac{1}{3} \end{bmatrix}, \] then the value of \[ \det(B^{-1}) \] is: 

      • \(\frac{1}{3}\)
      • \(\frac{1}{9}\)
      • \(3\)
      • \(9\)

    • 2.

      For two vectors \(\vec{a}\) and \(\vec{b}\):  

      Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

        • Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
        • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
        • Assertion (A) is true, but Reason (R) is false.
        • Assertion (A) is false, but Reason (R) is true.

      • 3.

        Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not. 


          • 4.
            If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]


              • 5.
                A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.


                  • 6.

                    The domain of \[ f(x)=\cos^{-1}(2x-5) \] is: 

                      • \([-1, 1]\)
                      • \([4, 6]\)
                      • \([-7, -3]\)
                      • \([2, 3]\)
                    CBSE CLASS XII Previous Year Papers

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