Perimeter and Area End of Chapter Class 9 Maths NCERT Solutions

The Perimeter and Area End-of-Chapter solutions solve all 27 mixed problems from the new Ganita Manjari book. This page gives clear steps for the NCERT Solutions Class 9 Maths Chapter 6 Perimeter and Area End of Chapter, so you can revise the full chapter and test yourself before the exam.

• Questions solved: all 27 End-of-Chapter problems that mix every idea in the chapter
• Main skills: Heron's formula, wheels and distance, and shaded circle regions
• How it links: it joins the three exercise sets into one full-chapter revision

These solutions are written by subject teachers, matched to the 2026-27 NCERT book, and checked line by line so a Class 9 student can follow each step.

What Does Class 9 Maths Chapter 6 Perimeter and Area End of Chapter Cover?

The End-of-Chapter set is the longest part of Perimeter and Area. It pulls together circles, triangles, and area proofs into one revision block. You use Heron's formula, the converse of Pythagoras, and the distance a wheel covers in one turn. The later questions ask for the shaded area in figures built from squares, semicircles, and quarter circles.

Video Walkthrough

Source: Vedantu CBSE 10th on YouTube

Perimeter and Area End-of-Chapter Question Breakdown

The 27 questions fall into a few clear groups. The list below shows what each group asks, so you can plan your revision.

• Triangle area (Q1 to Q6): area by base and height, by Heron's formula, and the 7, 24, 25 right-triangle check.
• Wheels and distance (Q7 to Q9): how far a bicycle or car wheel travels, plus a quadrant area from a given circumference.
• Area proofs (Q10 to Q14): equal area and perimeter, the parallelogram rule, the trapezium rule, and the area of a kite.
• Fractions and fitting (Q15 to Q19): fitting congruent shapes and finding what fraction of a figure is shaded.
• Shaded circle regions (Q20 to Q27): areas from quarter circles, semicircles, and concentric circles inside squares and rectangles.

Sample Solved Question from the End-of-Chapter Set

Here is Question 6 from the End-of-Chapter set, solved step by step, so you can see the method.

Question: The sides of a triangle have lengths 7 cm, 24 cm, and 25 cm. Find its area in two different ways.

Step 1. Test for a right angle with the converse of Pythagoras: 7² + 24² = 49 + 576 = 625 = 25². So the angle between the 7 cm and 24 cm sides is 90^∘.

Step 2. Method 1 uses the two legs as base and height: area = 12× 7 × 24 = 84 sq cm.

Step 3. Method 2 uses Heron's formula. The semi-perimeter is s = 7+24+252 = 28, so area = √28(28-7)(28-24)(28-25) = √7056.

Final answer. Both methods give √7056 = 84 sq cm, so the area is confirmed.

How to Use These Perimeter and Area End-of-Chapter Solutions

Collegedunia gives you the full End-of-Chapter answers as short, checked steps. Try each problem on paper first, then open the solution to compare your method with ours.

• Attempt the whole set once, then use the Collegedunia solutions to mark yourself.
• For a shaded-area figure, name every piece before you add or subtract areas.
• Redo any problem you got wrong the next day without looking at the steps.

More Class 9 Maths Perimeter and Area Solutions

Use the table below to open the full chapter page or any exercise of Perimeter and Area.