The Linear Polynomials Exercise 2.1 solutions cover all 5 questions from the new Ganita Manjari book. This set is about reading the degree, coefficients, and constant term of a polynomial. Use these NCERT Solutions Class 9 Maths Chapter 2 Linear Polynomials Exercise 2.1 answers to check each step and build a strong start.

  • Questions solved: all 5 questions on degree, coefficients, and the constant term.
  • Main skills: reading the highest power and picking out the number in front of a term.
  • Links to chapter: these basics are needed before you form and solve linear equations.

These solutions are prepared by subject teachers, matched to the current 2026-27 NCERT, and checked step by step so a Class 9 student can follow each line.

What Does Class 9 Maths Chapter 2 Linear Polynomials Exercise 2.1 Cover?

This exercise is the reading part of the chapter. You learn to name the parts of a polynomial. The degree is the highest power of the variable. A coefficient is the number multiplied by a power of the variable. The constant term is the part with no variable, and you can find it by putting the variable equal to 0. Once these names are clear, the rest of Linear Polynomials becomes easy.

Video Walkthrough

Source: PW Class 9 - NEEV on YouTube

Linear Polynomials Exercise 2.1 Question Breakdown

The exercise has five short questions. Each one tests one idea, so it is a quick set to finish.

QuestionWhat it asks
Question 1Find the degree of four given polynomials.
Question 2Write your own polynomials of degree 1, 2, and 3.
Question 3Find the coefficients of x2 and x3 in a polynomial.
Question 4Find the coefficient of z in 4z3 + 5z2 - 11.
Question 5Find the constant term of 9x3 + 5x2 - 8x - 10.

Sample Solved Question from Exercise 2.1

Here is Question 5, solved step by step, so you can see how to read the constant term.

Question: What is the constant term of the polynomial 9x3 + 5x2 - 8x - 10?

Step 1. Split the polynomial into its terms. The terms 9x3, 5x2, and -8x each carry the variable x.

Step 2. Find the term with no variable. Only -10 has no x in it.

Step 3. Read it with its sign. The constant term is -10.

Step 4. Check by putting x = 0. This gives 9(0)3 + 5(0)2 - 8(0) - 10 = -10, which matches.

Final answer. The constant term is -10.

Quick Tip: To find any constant term fast, put the variable equal to 0. Every term with a variable turns to 0, and the number left behind is the constant term, sign included.

How to Use These Linear Polynomials Exercise 2.1 Solutions

Try each question on your own first, then open the Collegedunia solution to check your working. This keeps your practice honest and shows you exactly where a slip happened.

  • Solve the question yourself, then match your answer line by line.
  • Note the small rules, like a missing term having coefficient 0.
  • Revise this set before your Class 9 annual exam to keep the basics sharp.

More Class 9 Maths Linear Polynomials Exercise 2.1 Solutions

Use the table below to open the full chapter or any other exercise of Linear Polynomials.

Linear Polynomials Exercise 2.1 NCERT Solutions FAQs

Ques. How many questions are there in Class 9 Maths Exercise 2.1?

Ans. Exercise 2.1 has 5 questions. They cover the degree, coefficients, and constant term of a polynomial. Collegedunia solves all of them.

Ques. How do I find the degree of a polynomial in Exercise 2.1?

Ans. The degree is the highest power of the variable. In y3 + 2y - 1 the powers are 3, 1, and 0, so the degree is 3.

Ques. What is the constant term in a polynomial?

Ans. The constant term is the part with no variable. You can find it by putting the variable equal to 0, which removes every other term.

Ques. Can I download the Exercise 2.1 solutions PDF?

Ans. Yes. The Linear Polynomials Exercise 2.1 solutions PDF is free on this page, so you can revise offline before your Class 9 exam.