TERNA Nerul Maharashtra JEE Main 2026 Cutoff : Check Category-wise and Round-wise Cutoff

The Maharashtra JEE Main 2025 Cutoff for TERNA Nerul in the General category ranges from 18447 to 50851 for admission to its BE programs. For the most competitive courses, the Round 1 cutoff for BE Computer Engineering was 18447, with the last round cutoff at 19333. The admission cutoff for BE Artificial Intelligence and Data Science started at 19347 in Round 1 and closed at 19099 in the last round.

Other programs such as BE (Information Technology), BE Electronics & Telecom Engineering, and BE Electronics Engineering had cutoff ranks falling between 20425 and 45310. Branches including BE Mechanical Engineering, BE Mechatronics Engineering, and BE Civil Engineering recorded cutoffs in the range of 39383 to 50851.