NCERT Solutions for Class 11 Maths Chapter 6 Exercise 6.1

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Class 11 Maths NCERT Solutions Chapter 6 Linear Inequalities Exercise 6.1 is based on following concepts:

Inequalities
Algebraic Solutions of Linear Inequalities in 1 Variable and their Graphical Representation

Download PDF NCERT Solutions for Class 11 Maths Chapter 6 Linear Inequalities Exercise 6.1

Check out the solutions of Class 11 Maths NCERT solutions Chapter 6 Linear Inequalities Exercise 6.1

Read More: NCERT Solutions For Class 11 Maths Chapter 6 Linear Inequalities

Also check other Exercise Solutions of Class 11 Maths Chapter 6 Linear Inequalities

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Unit Related Important Topics
Solving Inequalities	Relation between Degree and Radian	Sequence and Series

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CBSE CLASS XII Related Questions

1.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]
- local maximum value is 2
- local minimum value is \( -2 \)
- local maximum value is \( -2 \)
- local minimum value \( < \) local maximum value
View Solution
2.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]
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3.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]
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4.
For a square matrix \(A\), \[ (3A)^{-1}= \]
- \( 3A^{-1} \)
- \( 9A^{-1} \)
- \( \frac{1}{3} A^{-1} \)
- \( \frac{1}{9} A^{-1} \)
View Solution
5.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
6.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.
View Solution

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NCERT Solutions For Class 11 Maths Chapter 6: Linear Inequalities

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