Electromagnetic Induction And Alternating Currents JEE Mains Questions - List Of Most Asked Questions With Solutions

NTA will shortly release the JEE Main Syllabus 2025 at jeemain.nta.ac.in. Last Year, the complete syllabus of JEE Main underwent some major changes. According to the latest syllabus guidelines, the weightage of Physics has dropped to 22.5%. Due to these changes in the syllabus, certain shifts in chapter-wise weightage have been observed. Electromagnetic Induction and Alternating Current are among such topics. It’s among the least weightage topics in JEE Main Physics Syllabus 2025. This chapter holds 1.39% weightage in the whole syllabus.

  • Electromagnetic Induction and Alternating Current is a part of the General Physics section, and every year around 2-3 questions are asked from this chapter. Due to the drop in weightage, you can expect 1-2 questions in JEE Main 2025.
  • Electromagnetic Induction and Alternating Current in JEE Mains Physics Syllabus 2025 covers all the basic concepts on units and measurements, fundamentals of units, dimensions etc.

Aspirants consider Electromagnetic Induction and Alternating Current as one of the Easiest Chapters in Physics for JEE Main 2025. Even though this chapter has the least weightage in the syllabus, to develop a strong foundation in physics, this particular chapter plays a pivotal role. Hence the candidates need to develop a clear understanding of this chapter. The list of most asked questions from this chapter will help the students with their preparation.

Must Check News on JEE Main Physics:

Some important topics for JEE Main Electromagnetic Induction and Alternating Current include:

  • Faraday's Law of Electromagnetic Induction
  • Lenz's Law
  • Self-Inductance and Mutual Inductance
  • Eddy Currents
  • AC Generator and Transformer
  • EMI (Electromagnetic Induction) and its applications
  • LR Circuits with AC
  • LC Oscillations and Resonance

Electromagnetic Induction and Alternating CurrentJEE Mains Question-List Of Most Asked Questions With Solutions

In the (JEE) Main, the topic of Physics and Measurement often features questions that have appeared multiple times in previous years. Many questions in this section are either repeated or follow similar patterns, with only minor changes, such as different numerical values or slight modifications in wording.Certain questions have been repeated as many as five times.

Here are some of the most frequently asked and repeated questions:

Question: A coil of inductance 0.5 H and resistance 100 Ω is connected to a 240 V, 50 Hz AC supply. What is the peak current in the circuit?

Solution:

Correct answer: 2.26 A. Explanation: I_peak = V_peak / Z, where Z is the impedance and V_peak = √2 × Vrms.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

A 50 Hz AC current passes through a 20 H inductor. What is the reactance of the inductor?

Solution:

Correct answer: 6280 Ω. Explanation: Inductive reactance (XL) = 2πfL, where f is frequency and L is inductance.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question

A 100 μF capacitor is connected to a 50 V, 50 Hz AC supply. What is the capacitive reactance?

Solution:

Correct answer: 31.83 Ω. Explanation: XC = 1 / (2πfC), where f is frequency and C is capacitance.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

An AC voltage of 220 V, 50 Hz is applied to a series circuit containing a 60 Ω resistor and a 0.1 H inductor. Calculate the impedance of the circuit.

Solution: Correct answer: 94.87 Ω. Explanation: Z = √(R² + (XL)²), where XL = 2πfL.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

In an AC circuit, a 0.01 H inductor and 100 Ω resistor are connected in series with a 200 V, 50 Hz AC supply. What is the phase difference between the current and voltage?

Solution:

Correct answer: 11.42°. Explanation: Phase angle = tan⁻¹(XL/R), where XL = 2πfL.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

A coil with inductance 1 H and resistance 100 Ω is connected in series with a 200 V, 50 Hz AC supply. What is the power factor of the circuit?

Solution

: Correct answer: 0.447. Explanation: Power factor = R / Z, where Z = √(R² + (XL)²).

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

An alternating voltage of 220 V, 50 Hz is applied to a series LCR circuit with L = 50 mH, C = 100 μF, and R = 30 Ω. What is the resonant frequency of the circuit?

Solution:

Correct answer: 71.46 Hz. Explanation: Resonant frequency (f₀) = 1 / (2π√(LC)).

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

A transformer has 500 turns in the primary coil and 1000 turns in the secondary coil. If the primary voltage is 200 V, what is the secondary voltage?

Solution:

Correct answer: 400 V. Explanation: V_s / V_p = N_s / N_p, where N is the number of turns.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

The power dissipated in a circuit with a 100 Ω resistor, connected to a 220 V AC source with frequency 50 Hz, is?

Solution: Correct answer: 484 W. Explanation: P = V² / R.

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

Question:

An AC circuit consists of a resistor of 30 Ω, an inductor of 0.2 H, and a capacitor of 50 μF connected in series. The supply voltage is 100 V at 50 Hz. What is the total impedance of the circuit?

Solution:

Correct answer: 35.82 Ω. Explanation: Z = √(R² + (XL - XC)²), where XL = 2πfL and XC = 1 / (2πfC).

(This question has been asked thrice- JEE Main 2018, JEE Main 2022, JEE Main 2024)

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