Altitude and Median of Triangle: Definition & Properties

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Collegedunia Team

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Altitude and median of a triangle are two distinct concepts that are often confused to be equal or the same. Though both of them have equal importance while studying different aspects of triangles, they are not the same rather than in a rare case. Median begins from a vertex whereas an altitude is often referred to as beginning from a side of the triangle. But both the median and altitude touch the vertex and a side of the triangle. Some of the factors make median and altitude interesting parts of a triangle. 

Key Terms: Triangle, Perpendicular Line, Heights, Median, Altitude, Area of Triangle


Triangle

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Triangle is a closed geometric figure with three sides. The points at which the sides meet are known as the vertex (plural, vertices). A triangle may form any angle at the vertices, but the sum of all angles will be equal to 180°. With the help of the length of a side and altitude, one can measure the area of a triangle.

Also read: Triangle and its types


Altitude of a triangle

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Altitude is the perpendicular line drawn from a vertex to the opposite side of the triangle. A perpendicular line will always make a 90â° with the side on which it intersects. Since a triangle has three sides and three vertices, a triangle would have 3 altitudes. Altitude helps in calculating the area of a triangle,

 Area of a triangle = ½ x Base x Altitude


Median of a triangle

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The median of a triangle is a line segment drawn from a vertex to another point on the opposite side of that vertex so that the line segment divides the opposite side into two halves.

In the above figure, AR is a line segment that divides side BC into two halves, that is, BR and RC. Similarly, all the three medians divide the sides into equal halves.

With the help of the length of sides, we can find the length of a median, using the below formula:

Length of median = √(2b²+ 2c²- a²)/4

Where, a, b and c are sides of the triangle and ‘a’ is the side to which the median is drawn.


Properties of median and altitude

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The altitude and median of a triangle have different properties as a part of the triangle. The properties can be different for different kinds of triangles, but there are some features or key properties that make them identifiable.

  • Like the median, there would be 3 altitudes in a triangle. In other words, the number of sides in a triangle would be equal to the number of altitudes.
  • The angle that an altitude makes with the opposite side would always be 90 degrees.
  • If all the altitudes of a triangle are drawn at a time, then the three altitudes will surely intersect at a point called the orthocentre.
  • Altitude is a part of a triangle that always needn’t be within the sides of a triangle.
  • Altitude is a basic component that helps to calculate the area of a triangle.
  • In an equilateral triangle, the altitude is the same as the median.

There are some properties of a median that may be defined as its characteristics. These properties include:

  • An altitude begins from the vertex of a triangle and ends at the point of the opposite side which divides the opposite side equally.
  • The area of the two parts formed by drawing a median (which would be two triangles) would always be equal.
  • The number of medians in a triangle would be always equal to the number of vertices in the triangle.
  • If three medians are drawn at a time, they will surely meet at a point of the triangle.(Centroid) 
  • Areas of the number of smaller portions that a median creates within a triangle would be always equal.
  • In an equilateral triangle, the median is the same as the altitude.

 Things to remember

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  • The altitude of a triangle is the perpendicular line drawn from a vertex of the triangle to the opposite side. In other words, altitude represents the height of the triangle.
  • Altitude is used to calculate the area of a triangle, together with the length of the base to which the altitude is drawn.
  • A Median is a line segment drawn from the centre of a side of the triangle to the opposite vertex. In other words, the median divides the side into two halves.

Length of a median can be calculated by the formula,

Length of median = √ (2b²+ 2c²- a²)/4

Where, a, b and c are sides of the triangle and ‘a’ is the side to which the median is drawn.

  • In the case of an equilateral triangle, the median of the triangle is the same as the altitude of the triangle.

Also read: Equilateral triangle


 Sample questions

Ques. What is the major difference between the altitude and median of a triangle? (1 mark)

Ans. An altitude is a line that is a perpendicular line drawn from a side of a triangle to the vertex opposite that side. Altitude is referred to as the height of the triangle. Whereas a median is a line drawn for a vertex to the point on the opposite side which makes the side divide into two equal parts.

Ques. What are the intersection points of medians and intersection points of altitudes called? (2 marks)

Ans. In a triangle, there would be 3 medians that always lie within the triangle. When these entire three medians of the triangle are drawn at a time, they intersect at a common point called the centroid.

Altitudes of a triangle also meet a common point of the triangle, which may not be always internal to the triangle. This point is called the orthocentre of the triangle.

Ques. State some interesting properties of the median of a triangle. (3 marks )

Ans. A Median is a line drawn from a vertex of the triangle to the centre point of the opposite side. Some of the interesting features of the median are:

  • A median divides the opposite side into two equal parts.
  • Like the opposite line, the area of the two triangles formed would always be equal.
  • The number of medians in a triangle would be always three in number or equal to the number of vertices in the triangle.
  • If three medians are drawn at a time, it will surely meet at the centroid of the triangle.
  • The number of smaller triangles that the three medians create within a triangle would be always equal in area.

Ques. Explain step by step, what happens to the area of a triangle when each median is drawn. (3 marks)

Ans.

Consider a triangle ABC.

When a median AR is drawn, the triangle ABC is divided into two triangles (Δ ABR & Δ ACR).

Area of Δ ABR = Area of Δ ACR.

Similarly, when we draw median BQ,

Area of Δ BAQ = Area of Δ BCQ.

Also, when we draw the median CP,

Area of Δ CBP = Area of Δ ABQ.

Thus, on drawing all the three medians, the total triangle will be divided into.

Ques. ABC is a triangle with BC as the base and OA as its altitude. If it is further stated that the BC = 12cm and OA is 2 times the 3/4th of BC, will this help to calculate the area of that triangle? (3 marks)

Ans. 

Area of a triangle = ½ x Base x altitude

In the given Δ ABC,

Base, BC = 12 cm

Altitude, OA = 2 x ¾ x BC

= 2 x ¾ x 12

= 18 cm

Therefore, the area of Δ ABC = ½ x BC X OA

= ½ x 12 x 18

= 108 cm²

Ques. A triangle DEF had DE = EF = ED. If DE was 12 cm, what would be the altitude of that triangle? (4 marks)

Ans. 

Given in ΔDEF, the sides DE = EF = ED= 12cm.

 Therefore, Δ DEF is an equilateral triangle.

Area of an equilateral triangle = a² x √3/2

Where, a = length of the sides

Area of Δ DEF = 12² x √3/2

= 144 x √3/2

= 176.36 cm ²

Also, area of a triangle = ½ x base x altitude

Here, 176.36 = ½ x 12 x altitude

Therefore, Altitude = 29.39 cm

Ques. Δ GHI has sides GH =3 cm, HI = 4cm IG = 4.5 cm. Then what would be the length of the median IO? (5 marks)

Ans.

Length of median = √(2b²+ 2c²- a²)/4

Where, a, b and c are sides of the triangle and ‘a’ is the side to which the median is drawn.

In the Δ GHI,

a = GH = 3 cm

b = 4 cm

c = 4.5 cm

(Note: values of ‘b’ and ‘c’ are interchangeable.)

Therefore,

Height of IO = √[(2x 4² + 2 x 4.5² )- 3] / 4

= √ [52.25 – 3] / 4

= 1.75 cm

Ques. The median of triangle ABC is given as 4 cm. If AB = 34cm and BC= 23cm, what would be the length of CA, to which the median is drawn? (5 marks)

Ans. 

Length of median = √(2b²+ 2c²- a²)/ 4

Where, a, b and c are sides of the triangle and ‘a’ is the side to which the median is drawn.

Here, 4cm = √ (2b²+ 2c²- a²)/4

→ 4 cm= √ (2 x 34²+ 2 x 23²- a²)/4

→ 4 cm = √ (3370-a²)/4

a = 42.05 cm

Ques. The area of a triangle is given as 24cm². If the base has 32cm in length, what would be the length of the altitude? (3 marks)

Ans.  

Area of a triangle = ½ x Base x altitude

Here area of triangle = 24 cm²

Base = 32 cm

i.e. 24 cm² = ½ x 32 cm x Altitude

Therefore, altitude = 24 x 2 /32

= 1.5 cm

Ques. In a triangle, ABC, median AO = 4cm, and a 90-degree line drawn from the vertex B to the median is 3.4 cm. Then what would be the area of the triangle BAO? (3 marks )

Ans. 

The median AO will divide Δ ABC into two equal triangles, Δ AOB & Δ AOC.

Considering Δ AOB,

AO = base = 4 cm

Altitude = 3.4 cm (perpendicular drawn to the base)

Therefore, area of Δ AOB = ½ x 4 x 3.4

= 6.8 cm²

Since median divide a triangle into two equal triangles,

Area of Δ AOB = area of Δ AOC

Therefore,

Area of Δ ABC = 2 x area of Δ AOB

= 2 x 6.8

= 13.6 cm ²

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