
Content Curator
A line is a collection of all possible points that may be found on it. The relationship between the various points of the lines is shown in a line equation. A line equation specifies the requirements that must be met by the points. The line equation is an algebraic equation with two variables, x and y. A straight-line equation has x and y terms. If the equation of the line fulfills the point P(x,y), then the point P is on the line l.
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Keywords: Straight Lines, Point of Origin, Slope, Coordinates, Collinearity, Intercepts, Plane, Perpendicular
Different Forms of the Equations of Line
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Vertical Line
A vertical line at a distance of v from the y-axis has the equation x = v or x = -v. The location of the line determines the sign.

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Horizontal Line
A horizontal line at a distance of h from the x-axis has the equation y = h or y = -h. The location of the line determines the sign.

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Point-Slope Form
The requirement for a point to lie on the line is given by this version of the equation. Assume A (x0, y0) is a fixed point on the slope m line l. Consider another point, such as B. (x, y). If and only if, the coordinates of the point B (x, y) fulfill the equation, it will lie on the line l.
m = (y − y0) / (x − x0)
y − y0 = m (x − x0)

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Two-points Form
Consider a line l that connects the coordinates A (x1, y1) and B (x2, y2) (x2, y2). Consider the letter C. (x, y). If they fulfill the requirement of collinearity, this point will satisfy the condition to lie on.
AC Slope = BC Slope = AC Slope
Required equation= (y − y1) / (x − x1) = (y2 − y1) / (x2 − x1) or, (y − y1) = (x − x1) (y2 − y1) / (x2 − x1)

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Slope-Intercept Form
The distance at which a line meets the y-axis is known as the y-intercept. An x-intercept is the point where a line intersects the x-axis. Assume a line l crosses the y-axis at a distance 'c' from the origin and has a slope of m. The equation for the line l that passes through the point (0, c) is.

m = (y − c) / (x − 0) or, y = mx + c
Consider a line l intersecting the x-axis at a point 'd' from the origin with a slope of m. The equation for the line l that passes through the point (d, 0) is.

m = (y − 0) / (x − d) or, y = m(x − d)
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Intercept Form
Assume that a line l with slope m intersects the y-axis at a distance of 'c' from the origin and the x-axis at a distance of 'd'. The equation for the line l that passes through the points (0, c) and (d, 0) is
(y − y1) / (x − x1) = (y2 − y1) / (x2 − x1)
Or, (y − 0) / (x − d) = (c − 0) / (0 − d)
y/c + x/d = 1

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Normal Form
Let's say we have a line l in the XY plane. The angle with the positive direction of the x-axis is known as well as the perpendicular distance (normal) from the origin to the line.
The length of the normal OA is p in this case, and it forms an angle with the x-axis. (p cosα, p sinα) will be the coordinates of A. The angle OA is perpendicular to the line l. tanα = slope of line l = -1 / slope of OA = -1 We get the needed line equation, x cosα + y sinα = p, after solving.

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General Equations of Line
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Ax + By + C = 0 is the universal equation for any line, where x and y are variables and A and B are not both zero. It's fascinating to learn that a line's general equation may be reduced to any type of equation.
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Slope-Intercept Form
Ax + By + C = 0 may be simplified to y = (A/B) x C/B (of the form y = mx + c) if B ≠ 0. The y-intercept, c = C/B, and the slope of the line, m = -A/B. If B = 0, the x-intercept equals x = -C/A.
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Intercept Form
Ax + By + C = 0 may be simplified to (x/ (-C/A)) + (y/ (-C/B)) = 1 (of the form x/a + y/b = 1) when C ≠ 0. The x-intercept is equal to -C/A, while the y-intercept is equal to -C/B. A = B = 0 if C = 0 and Ax + By = 0. It depicts a line that passes through the origin.
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Normal Form
x cosα + y sinα = p is the standard form of the equation. We get cosα = A/(A2 + B2)1/2, sinα = B/(A2 + B2)1/2, and p = ±C /(A2 + B2)1/2 when we reduce it to Ax + By + C = 0.
Things to Remember
- A line in a coordinate plane forms two extra angles with the x-axis. The inclination of the line is the angle (θ) formed by the line l in the positive direction of the x-axis and measured anticlockwise.
- y = a, where a is the y – coordinate of the line's points, is the equation for horizontal or parallel lines to the X-axis. The equation x = a applies to a straight line that is vertical or parallel to the Y-axis, where a is the x-coordinate of the line's points.
- A general linear equation or general equation of a line is any equation of the form Ax + By + C = 0, where A and B are not both zero at the same time.
- The y axis is a straight line that passes through the origin and has a slope of 90°, 270°, or – 90°. So, depending on the sort of data we have for a line, straight lines may be represented in a variety of ways. The following are the several types of line of equations: Standard Form, General Form, Point-Slope Form, Slope-Intercept Form, and Two Point Form are the different types of forms.
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Sample Questions
Ques: The line connecting the points (–2, 6) and (4, 8) is perpendicular to the line connecting the points (8, 12) and (–2, 6) (x, 24). Calculate the value of x. (3 marks)
Ans: Points given are (-2, 6) and (4, 8)
Slope of the line is.
m1 = 8-64--2=26=13
Now, the slope of the line through (8, 12) and (x, 24) is.
m2 = 24-12x-8=12x-8
As both the lines are perpendicular
m1 m2 = -1
13×12x-8= -1
x = 4
Ques: Find the equation of the line passing through the points (-1, 0) and (-4 , 12). (3 marks)
Ans: The slope of the line is given by
m=y2 - y1x2- x1=12-0-4--1=-123= -4
Point-slope Form Formula
y – y1 = m(x – x1)
y - 0 = - 4(x - (-1))
y + 4 x = - 4
Ques: Determine the equation of the line passing through (– 2, 3) and having a slope of – 4. (3 marks)
Ans: m = -4 and (x0 , y0) = (-2, 3)
Using Slope-intercept Form Formula,
y-3 = -4 (x + 2)
or
4x + y + 5 = 0
Hence, the required equation is 4x + y + 5 = 0.
Ques: Determine the equation of the line whose slope is 8 and the point's coordinates are (3, 5). (3 marks)
Ans: m= 8, (x , y) = (3, 5)
We know, formula of the equation of a line is:
y – y1 = m (x – x1)
y – 5 = 8 (x – 3)
y – 5 = 8x – 24
8x – y = 19
8x – y – 19 = 0
Ques: Find the line's equation, which has –3 and 2 intercepts on the x- and y-axes, respectively. (2 marks)
Ans: a= -3 and b= 2
Using Intercept Form,
x-3+y2=1
2x – 3y + 6 = 0
Ques: Find the equation for a straight line with an intercept 3 in the negative direction of the y-axis and a 120° angle to the x-axis. (2 marks)
Ans: y = x × tan(120°) +(-3)
y +x√3 + 3 = 0
Thus, the required equation is y +x√3 + 3 = 0
Ques: Find the equation for a line whose perpendicular distance from the origin is 4 units and whose normal creates a 15° angle with the positive x-axis. (3 marks)
Ans: p= 4 and ω = 15o
cos15°=3+122
sin15°=3-122
Using Normal Form,
xcos15°+ysin15°=4 or3-122x+3-122y=4
3+1x+3-1y=82
Ques: What will be the equation of the lines with tan θ = 1/2, where θ is the inclination of the line and y- intercept is -3/2 and x- intercept is 4? (3 marks)
Ans: When,
m= tan θ= 1/2 and y- intercept c = -3/2
Using Slope-intercept Form,
y=12x-32
2y – x + 3 = 0
When,
m= tan θ = 1/2 and d= 4
Using Slope-intercept Form,
y=12(x-4)
2y -x + 4 = 0







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