NCERT Solutions For Class 11 Mathematics Chapter 4: Principle of Mathematical Induction

Collegedunia Team logo

Collegedunia Team

Content Curator

NCERT Solutions for class 11 mathematics Chapter 4 Principles of Mathematical Induction are given in the article. Mathematical Induction is a technique of proving a statement, theorem or formula which is assumed to be true, for each and every natural number n. Important concepts covered in the article are Complex NumbersComplex Numbers and Quadratic Equations, and Algebraic Operations On Complex Numbers.

Download: NCERT Solutions for Class 11 Mathematics Chapter 4 pdf


Class 11 Maths NCERT Solutions Chapter 4 Principles of Mathematical Induction

Class 11 Maths NCERT Solutions Chapter 4 Principles of Mathematical Induction are as below:

Ncert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert SolutionsNcert Solutions

Also check: Principles of Mathematical Induction Important Questions


Important Topics: Class 11 Maths Chapter 4 Principles of Mathematical Induction

Class 11 Maths NCERT Solutions Chapter 4 Principles of Mathematical Induction cover the key steps to prove a theorem. These are as follows:

  • Base step: To prove P(1) is true.
  • Assumption step: Assume that P(k) is true for some k in N.
  • Induction step: Prove that P(k+1) is true.

After proving these 3 steps, it can be concluded that "By the principle of mathematical induction, P(n) is true for all n in N". The assumption that we make in the second step that P(n) holds for some natural number n = k is called induction hypothesis.

Please note: As per Class 11 Maths Updated Syllabus 2022-23, Chapter 4 Principles of Mathematical Induction has been omitted.

Also check:

CBSE CLASS XII Related Questions

  • 1.

    A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 


      • 2.
        Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).


          • 3.
            Find:

            If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

              • \(0\)
              • \(-2\)
              • \(-1\)
              • \(2\)

            • 4.
              Find:

              If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

                • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
                • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
                • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
                • \(p = 0, \, q = 0\)

              • 5.

                An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
                Based on the above information, answer the following questions :


                  • 6.
                    Find:

                    The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                      • \(-\frac{\pi}{2}\)
                      • \(-\frac{\pi}{4}\)
                      • \(\frac{\pi}{4}\)
                      • \(\frac{\pi}{2}\)
                    CBSE CLASS XII Previous Year Papers

                    Comments


                    No Comments To Show