NCERT Solutions for Class 11 Maths Chapter 10 Exercise 10.3

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Class 11 Maths NCERT Solutions Chapter 10 Straight Lines Exercise 10.3 is based on forms of Equation of a Line. Following concepts are covered under this topic:

  • General Equation of a Line
  • Distance of a Point From a Line

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CBSE CLASS XII Related Questions

  • 1.

    \( \int e^{x}\left( \frac{2+\sin 2x}{1+\cos 2x} \right) dx \) is equal to :

      • \( \log \cos 2x + C \)
      • \( \sec^{2} 2x + C \)
      • \( e^{x}\tan x + C \)
      • \( e^{x}\cot x + C \)

    • 2.

      Find the product of the maximum and minimum values of the function \( f(x) = \cos x - \frac{1}{2}\cos 2x,\ x \in \left[0, \frac{\pi}{2}\right] \).


        • 3.

          For the following Linear Programming Problem, shade the feasible region on the graph and find the coordinates of its corner points :

          Minimize \(Z = 18x + 10y\)

          subject to constraints

          \[ \begin{aligned} 4x + y &\ge 20 \\ 2x + 3y &\ge 30 \\ x, y &\ge 0. \end{aligned} \]


            • 4.

              If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that

              \[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]


                • 5.

                  For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :

                    • \(\frac{1}{2}\)
                    • \(\frac{3}{5}\)
                    • \(\frac{1}{5}\)
                    • \(\frac{3}{10}\)

                  • 6.

                    Solve the differential equation \( (x+y)\,dy + (x-y)\,dx = 0 \), given that \( y(1) = 1 \).

                      CBSE CLASS XII Previous Year Papers

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