NCERT Solutions for Class 8 Mathematics Chapter 3: Understanding Quadrilaterals

NCERT Solutions for class 8 Mathematics Chapter 3 Understanding Quadrilaterals are provided in the article below. Some of the important topics in the Understanding Quadrilaterals chapter include:

  1. Area of Rectangle
  2. Area of Square
  3. Exterior Angles of Polygon
  4. Properties of Hexagon
  5. Types of Polygon
  6. Rhombus
  7. Diagonal formula

Download PDF: NCERT Solutions for Class 8 Mathematics Chapter 3 pdf


NCERT Solutions for Class 8 Mathematics Chapter 3

NCERT Solutions for Class 8 Mathematics Chapter 3 Understanding Quadrilaterals is given below.

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NCERT Solutions for Class 8 Mathematics

Quadrilateral is any figure that has 4 sides and whose interior angles are 360 degrees. Quadrilaterals are divided into several categories such as:

  • Square: A square is a quadrilateral, or a special type of parallelogram, with all of its sides equal.
  • Rectangle: A rectangle is a quadrilateral with parallel and equal opposite sides.
  • Parallelogram: A quadrilateral with opposite parallel sides is known as a parallelogram (and therefore opposite angles equal).
  • Rhombus: A quadrilateral with four equal-length sides is known as a rhombus. Because of its characteristic of equality of length, it is also known as an equilateral quadrilateral.
  • Trapezoid: A trapezium is a quadrilateral having at least one pair of parallel sides that is convex in shape.

Area of Square = a2

Area of Rectabgle = Length x Breadth

Area of Parallelogram = Base x height

Area of Rhombus = ½ x diagonal 1 x diagonal 2

Area of Trapezium = ½ x (a + b) x h


NCERT Solutions for Class 8 Maths Chapter 3 Exercises

NCERT Solutions for Class 8 Maths Chapter 3 Exercises are given below.

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CBSE X Related Questions

  • 1.
    PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


      • 2.
        Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
        Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Assertion (A) is false, but Reason (R) is true.

        • 3.
          The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

            • 0
            • 1
            • 3
            • 2

          • 4.
            If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

              • $x^2 + 5x - 4$
              • $(x + 3) (-x + 8)$
              • $a(x^2 + 5x - 24)$
              • $x^2 - 24$

            • 5.
              Prove that :
              \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).


                • 6.
                  The natural number 1 is :

                    • a prime number.
                    • a composite number.
                    • prime as well as composite.
                    • neither prime nor composite.

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