JNTUA M.Tech Product Design & Development: Fees 2026, Course Duration, Dates, Eligibility

Anantapur, Andhra PradeshState UniversityEstd 2008
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Collegedunia Team

Content Curator | Updated 3+ months ago

M.Tech Product Design & Development at JNTUA is a 2 years, Full Time Degree program offered On Campus.

  • The total fees for the M.Tech Product Design & Development program at JNTUA is ₹ 60,000.
  • Students need to pay ₹ 30,000 in the first year.

NIRF Engineering ranking 2025, ranks JNTUA at 151-200 out of 300 in India.

Find detailed JNTUA M.Tech Product Design & Development fees, eligibility, admission dates, cutoff and ranking below.

Course HighlightsDetails
duration2 Years (Full Time)
course levelPG (Degree)
mode of studyOn Campus
total fees₹ 2.06 Lakhs
eligibilityGraduation + AP PGECET
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JNTUA M.Tech Product Design & Development Fees

JNTUA M.Tech Product Design & Development fees 2025 is ₹ 60,000 for the entire course duration.
  • This includes a total tuition fee of ₹ 60,000.
  • Candidates need to pay ₹ 30,000 in the first year.

Earlier, M.Tech Product Design & Development fees at JNTUA was ₹ 2 Lakhs (in 2020) for the entire course duration. This shows a fee decrease of ₹ 1.4 Lakhs over the year.

Quota:
Fee TypeTotal Amount (INR)
total fee₹2.06 Lakhs
* Fees is refundable

Important Dates for M.Tech Product Design & Development at JNTUA


Expired Events

EventsDates
AP PGECET Result date
May 14, 2026
AP PGECET Exam date
Apr 28, 2026 - Apr 30, 2026
Admission Timeline [ME/M.Tech]
Apr 01, 2026 - Apr 30, 2026
Check entrance exam dates for admission in M.Tech Product Design & Development at JNTUA -

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