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The change of base formula is used to change the base of a logarithm.
- A logarithm is defined as the power to which a base must be raised to yield a given number.
- We may have noticed two buttons in scientific calculators: "log" and "ln".
- "log" is a base 10 logarithm, while "ln" is a base e logarithm.
- However, calculating the logarithm of a number using bases other than 10 and e is not an option.
- This problem is solved by changing the base formula.
- It is also used for solving many logarithmic problems.
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Key Terms: Logarithm, Change of base formula, Ratio, Power, ln, log, Logarithm formula, Exponent, Exponential, Base, Number, Numerator, Denominator.
What is Change of Base Formula?
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The change of base formula is used to express a logarithm of a number with a specific base as the ratio of two logarithms, each with a base that differs from the original logarithm. This is a property of logarithms.
Change of Base Formula
The basic logarithm with a base is converted into two logarithms with a new and similar base. The change of base formula is given by
\(\LARGE \log_{a}b=\frac{\log _{c}b}{\log _{c}a}\)
The above formula can also be written as
\(\LARGE \log_{a}b \: .\: \log _{c}a = \log _{c}b\)
In the above formula
- The argument of the logarithm in the numerator is the same as that of the original logarithm.
- The argument of the logarithm in the denominator is the same as that of the base of the original logarithm.
- Both the numerator and denominator logarithms should have the same base, which can be any positive integer other than 1.

Read More: Change of base formula Hindi pdf notes
Change of Base Formula Derivation
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The following steps can help to understand the change in base formula derivation.
Let us assume that,
- \(\log_{b}a = p\)
- \(\log_{c}a = q\)
- \(\log_{c}b = r\)
On converting the above expressions into exponential form, we get
\(a =b^{\:p}, \: a=c^{\:q}, \:and \: b=c^ {\:q}\)
From the above first two equations, we have
\(b^{\:p} = c^{\:q}\)
Substituting \(b= c^{\:r}\), we get
\((c^{\:r})^p = c^{\:q}\)
\(\Rightarrow c^{\:rp} = c^{\:q}\)
\(\Rightarrow rp = q\)
\(\Rightarrow p= \frac {q}{r}\)
Substituting the values of p, q, and r, we get
\(\log_{b}a = \frac {\log_{c}a}{\log_{c}b}\)
Change of base formula pdf notes:
Solved Examples of Using Change of Base Formula
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| Ques. Solve \(3\log_{4}30\). Ans. Given \(3\log_{4}30\) Using the formula, \( \log_{b}a=\frac{\log _{c}a}{\log _{c}b}\), we get \(3\log_{4}30 = 3 \times \frac {\log_{10}30 }{\log_{10}4 }\) \(\Rightarrow 3\log_{4}30 = 3 \times \frac {1.48}{0.60}\) \(\Rightarrow 3\log_{4}30 = 7.4\) Ques. Solve \(\log_{32}16\). Ans. Given \(\log_{32}16\) Using the formula, \( \log_{b}a=\frac{\log _{c}a}{\log _{c}b}\), we get \(\log_{32}16 = \frac {\log_{10}16 }{\log_{10}32 }\) \(\Rightarrow \log_{32}16 = \frac {1.2}{1.5}\) \(\Rightarrow \log_{32}16 = 0.8\) |
Things to Remember
- A logarithm is defined as the power to which a base must be raised to yield a given number.
- "log" is a base 10 logarithm, while "ln" is a base e logarithm.
- The basic logarithm with a base is converted into two logarithms with a new and similar base.
- The change of base formula is given by \(\log_{b}a=\frac{\log _{c}a}{\log _{c}b}\).
- Both the numerator and denominator logarithms should have the same base, which can be any positive integer other than 1.
Also Read:
Sample Questions
Ques. What are the applications of the change of base formula in logarithms? (2 Marks)
Ans. The change of base formula is mostly used to convert the base of a logarithm to any other base. This is commonly used to calculate logarithms in bases other than 10 and "e" because the calculator only includes choices for calculating logarithms in bases 10 (log button) and e (ln button).
Ques. How to use Change of Base Formula? (2 Marks)
Ans. The basics of the formula change to the base is log b = [logc a] / [logc b]. To change the base of a logarithm, divide [log a] by [log b]. These logarithms can have any positive integer as their base.
Ques. Solve the following logarithm: 2log4 29. (2 Marks)
Ans. The given logarithm is, 2log4 29
Now using the change of base formula,
log b a = [log c a] / [log c b]
2 log4 29 = 2 × log10 29 / log 10 4
2log4 29 = 2 x 2.43 = 4.86
Ques. Simplify the given logarithm: log32 16. (2 Marks)
Ans. The logarithm given is,
log 32 16
Thus using a change of base formula,
log b a = [log c a] / [log c b]
log 32 16 = log 10 16 / log 10 32
= log 10 24 / log 10 25
= 4 log 10 2 / 5 log 10 2 [since, we know, log am = m log a]
= 4 / 5
Ques. Evaluate the value of log 64 8 using the change of base formula. (3 Marks)
Ans. Here the change of base formula is used to change the base to 10.
log b a = [log c a] / [log c b]
We know that log 10 x is the same as log x.
log 64 8 = log 10 8 / log 10 64
= log 8 / log 82
= log 8 / 2 log 8 [since, we know, log am = m log a]
= 1 / 2
Ques. Calculate log 9 8. Round your answer to 4 decimals. (2 Marks)
Ans. We cannot calculate log 9 8 directly so we apply the change of base formula to change the base to 10 so it can be calculated easily.
log b a = [log c a] / [log c b]
log 9 8 = log 10 8 / log 10 9
= 0.903 / 0.954
= 0.9465
Ques. Calculate the value of log 6 10 using the change of base formula. (2 Marks)
Ans. From the change of base formula, we have
log b a = [log c a] / [log c b]
log 6 10 = log 10 10 / log 10 6
= 1 / 0.778
= 1.285
Ques. Calculate the value of log 4 10 using the change of base formula. (2 Marks)
Ans. From the change of base formula, we have
log b a = [log c a] / [log c b]
log 4 10 = log 10 10 / log 10 4
= 1 / 0.602
= 1.66
Ques. Calculate the value of log 3 2 · log 4 3 · log 5 4 using necessary logarithm functions and formulae. (5 Marks)
Ans. Here we have to use the change of base formula in the multiplication form which is,
log b a · log c b = log c a
We apply this formula twice to evaluate the given logarithmic expression.\
The given logarithm expression is,
log 3 2 · log 4 3 · log 5 4
Solving the first two terms, we get,
log 3 2 · log 4 3 · log 5 4
Here, a=2, b=3, c=4;
Therefore, according to, log b a · log c b = log c a, we get,
log 3 2 · log 4 3 = log 4 2
Substituting this value in the given expression, we have
= log 4 2 · log 5 4
Now, on solving these two terms, we get,
log 4 2 · log 5 4
Here, a = 2, b = 4, c = 5;
Therefore, according to, log b a · log c b = log c a, we get,
log 4 2 · log 5 4 = log 5 2
Therefore, the value of log 3 2 · log 4 3 · log 5 4 is log 5 2.
Now we use the change of base in this form to change the base of this log 5 2 to 10 for further calculation.
log b a = [log c a] / [log c b]
Here, a = 2, b = 5, c = 10.
Thus, log 5 2 = log 10 2 / log 10 5
= 0.301 / 0.69897
= 0.99997
Ques. Evaluate the given logarithm and round your answer to the nearest thousandth. log 2 (1/50). (3 Marks)
Ans. The logarithm given is,
log 2 (1/50)
Thus by using the change of base formula,
log b a = [log c a] / [log c b]
log 2 (1/50) = log 10 (1/50) / log 10 2
= (log 10 1 - log 10 50) / log 10 2 [since we know log (a/b) = log a - log b]
= - log 10 50 / log 10 2 [since we know log 10 1= 0]
= - 5.644
Ques. Evaluate the given logarithm and round your answer to the nearest thousandth. log 3 (0.2). (3 Marks)
Ans. The logarithm given is,
log 3 (0.2)
Thus using the change of base formula,
log b a = [log c a] / [log c b]
log 3 (0.2)
= log 10 (0.2) / log 10 3
Now, log 10 (0.2) = log 10 (1/5)
= (log 10 1 - log 10 5) / log 10 2 [since we know log (a/b) = log a - log b]
= - log 10 5 / log 10 2 [since we know log 10 1= 0]
= - 1.465
Ques. Evaluate the given logarithm and round your answer to the nearest thousandth. log 7 (25). (3 Marks)
Ans. The logarithm given is,
log 7 25
Thus using the change of base formula,
log b a = [log c a] / [log c b]
log 7 25
= log 10 25 / log 10 7
Now, log 10 25 = log 10 52
= log 10 52 / log 10 2
= 2log 10 5 / log 10 2 [since, we know, log am = m log a]
= 1.654
Ques. Evaluate the value of log 3 2 · log 4 3 · log 5 4. (2 Marks)
Ans. Using the change of base formula, log b a ⋅ log c b = log c a.
We get
log 3 2 · log 4 3 · log 5 4
= log 4 2 · log 5 4
= log 5 2
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