NCERT Solutions for Class 11 Maths Chapter 12 Exercise 12.3

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Class 11 Maths NCERT Solutions Chapter 12 Introduction to Three Dimensional Geometry Exercise 12.3 is based on the topic Section Formula.

Download PDF NCERT Solutions for Class 12 Introduction to Three Dimensional Geometry Exercise 12.3

Check out the solutions of Class 11 Maths NCERT Solutions Chapter 12 Introduction to Three Dimensional Geometry Exercise 12.3

Read More: NCERT Solutions For Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry

Also check other Exercise Solutions of Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry

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Chapter Related Topics
Angle Between Two Plane	Angle between two lines	Angle between line and plane

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CBSE CLASS XII Related Questions

1.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.
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2.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.
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3.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]
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4.
If \[ B(\operatorname{adj} B)= \begin{bmatrix} \frac{1}{3} & 0 & 0\\ 0 & \frac{1}{3} & 0\\ 0 & 0 & \frac{1}{3} \end{bmatrix}, \] then the value of \[ \det(B^{-1}) \] is:
- \(\frac{1}{3}\)
- \(\frac{1}{9}\)
- \(3\)
- \(9\)
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5.
The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:
- \( e^{-3} \)
- \( -1 \)
- \( 1 \)
- \( -e^3 \)
View Solution
6.
Evaluate: \[ \cos\left[\sin^{-1}(-1)-\tan^{-1}(-\sqrt{3})\right]. \]
View Solution

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