NCERT Solutions for Class 11 Maths Chapter 12 Miscellaneous Exercises

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Class 11 Maths NCERT Solutions Chapter 12 Introduction to Three Dimensional Geometry Miscellaneous Exercises is based on the following concepts:

Coordinate Axes and Coordinate Planes in Three Dimensional Space
Coordinates of a Point in Space
Distance between Two Points
Section Formula

Download PDF NCERT Solutions for Class 12 Introduction to Three Dimensional Geometry Miscellaneous Exercises

Check out the solutions of Class 11 Maths NCERT Solutions Chapter 12 Introduction to Three Dimensional Geometry Miscellaneous Exercises

Read More: NCERT Solutions For Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry

Also check other Exercise Solutions of Class 11 Maths Chapter 12 Introduction to Three Dimensional Geometry

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Chapter Related Topics
Angle Between Two Plane	Angle between two lines	Angle between line and plane

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CBSE CLASS XII Related Questions

1.
At a birthday party, children are being served orange juice in conical cups, as shown in the figure.

Each cup is 15 cm deep and has a radius 5 cm. The juice is being poured into this cup at a rate of 0·1 cm3/s.
On the basis of the above information, answer the following questions :
2.
If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).
View Solution
3.
Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]
View Solution
4.
Find:

The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]
View Solution
5.
Find:

If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).
- \(0\)
- \(-2\)
- \(-1\)
- \(2\)
View Solution
6.
Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).
View Solution

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