NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for class 7 Mathematics Chapter 14 Symmetry are provided in the article below. If two or more parts of a figure are identical after folding or flipping then it is said to be symmetry. To be symmetrical the two halves of a shape must be of same shape and size. If the shape is not symmetrical then it is said to be asymmetrical. Some of the important topics in Symmetry chapter include:

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics Chapter 14 Symmetry is given below.

NCERT Solutions for Class 7 Mathematics

Symmetry: A figure is said to be symmetrical if one half of the figure is a mirror image of the other.

Depending on the lines of symmetry, symmetrical figures can be classified into:

No Line of Symmetry (for the asymmetrical figure)
One Line of Symmetry
Two Line of Symmetry
Multiple (more than 2) Line of Symmetry
Infinite Line of Symmetry

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

NCERT Solutions for Class 7 Maths Chapter 14 Symmetry Exercises is given below.

Read More:

Asymmetric Relation	Line of Symmetry
Line of Symmetry in a Rectangle	Line of Symmetry in Parallelogram

Class 7 Maths Guide:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
View Solution
2.
The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is
- \(1\)
- \(-5\)
- \(25\)
- \(\sqrt{5}\)
View Solution
3.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
View Solution
4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.
View Solution
5.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then
- \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
View Solution
6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is
- \(4 \text{ cm}\)
- \(4\sqrt{2} \text{ cm}\)
- \(8 \text{ cm}\)
- \(2\sqrt{2} \text{ cm}\)
View Solution

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NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

CBSE X Related Questions

1.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

2.
The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

3.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

5.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

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NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

CBSE X Related Questions

1.In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

2.The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

3.D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

4.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

5.If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

6.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

2.
The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

3.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

4.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

5.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is