NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for class 7 Mathematics Chapter 14 Symmetry are provided in the article below. If two or more parts of a figure are identical after folding or flipping then it is said to be symmetry. To be symmetrical the two halves of a shape must be of same shape and size. If the shape is not symmetrical then it is said to be asymmetrical. Some of the important topics in Symmetry chapter include:

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics Chapter 14 Symmetry is given below.

NCERT Solutions for Class 7 Mathematics

Symmetry: A figure is said to be symmetrical if one half of the figure is a mirror image of the other.

Depending on the lines of symmetry, symmetrical figures can be classified into:

No Line of Symmetry (for the asymmetrical figure)
One Line of Symmetry
Two Line of Symmetry
Multiple (more than 2) Line of Symmetry
Infinite Line of Symmetry

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

NCERT Solutions for Class 7 Maths Chapter 14 Symmetry Exercises is given below.

Read More:

Asymmetric Relation	Line of Symmetry
Line of Symmetry in a Rectangle	Line of Symmetry in Parallelogram

Class 7 Maths Guide:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
Find the H.C.F. and L.C.M. of 1530 and 2040.
View Solution
2.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)
View Solution
3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.
View Solution
4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.
View Solution
5.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).
View Solution
6.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).
View Solution

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NCERT Solutions for Class 7 Mathematics Chapter 9: Rational Numbers

NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

NCERT Solutions For Class 7 Mathematics Chapter 4: Simple Equations

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NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

CBSE X Related Questions

1.
Find the H.C.F. and L.C.M. of 1530 and 2040.

2.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

5.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

6.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).

Comments

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NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

CBSE X Related Questions

1.Find the H.C.F. and L.C.M. of 1530 and 2040.

2.Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

3.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

4.In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

5.If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

6.In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Find the H.C.F. and L.C.M. of 1530 and 2040.

2.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

4.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

5.
If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

6.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).