NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

NCERT Solutions for class 7 Mathematics Chapter 15 Visualizing Solid Shapes are provided in the article below. Plane shapes have two measurements like length and breadth which are called dimensions of a plane and therefore they are called two-dimensional shapes whereas a solid object has three measurements like length, breadth, height or depth. Hence, they are called three-dimensional shapes or 3-D shapes. Some of the important topics in this chapter include:

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

NCERT Solutions for Class 7 Mathematics Chapter 15 Visualizing Solid Shapes are given below.

NCERT Solution class 7 mathematics chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

Three dimensional figure: Three-dimensional figures are those which consist of length, breadth and height.

Some of the important three dimensional figures include:

Cube
Cuboid
Cone
Cylinder
Pyramid

Volume of Cube – a³

Volume of Cuboid – length x breadth x height

Volume of Cone – 1/3 $\pi$r²h

Volume of Cylinder – $\pi$r²h

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

NCERT Solutions for Class 7 Maths Chapter 15 Visualising Solid Shapes Exercises are given below.

Read More:

Visualising Solid Shapes MCQ	Measurement of Objects	Isomeric Sketch
Rectangular Pyramid	3D Shapes	Hexagon Formula

Read More:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is
- $50^\circ$
- $60^\circ$
- $45^\circ$
- $30^\circ$
View Solution
2.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.
View Solution
3.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is
- $\frac{5}{12}$
- $\frac{5}{6}$
- $1$
- $0$
View Solution
4.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
5.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.
View Solution
6.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals
- $x^2 + 5x - 4$
- $(x + 3) (-x + 8)$
- $a(x^2 + 5x - 24)$
- $x^2 - 24$
View Solution

View All

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NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

CBSE X Related Questions

1.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

2.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

3.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

4.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

5.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

6.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

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NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

​Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

CBSE X Related Questions

1.An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

2.Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

3.Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

4.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

5.In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

6.If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

Comments

SUBSCRIBE TO OUR NEWS LETTER

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

1.
An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

2.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

3.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

4.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

5.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

6.
If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals