
Content Curator
NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Exercise 7.2 is provided as a pdf in this article. Exercise 7.2 in Chapter 7 Cubes and Cube Roots includes finding cube roots by the prime factorization method.
Download PDF of NCERT Solutions for Class 8 Chapter 7 Cubes and Cube Roots Exercise 7.2
Also Read: NCERT Solutions For Class 8 Mathematics Chapter 7 Cubes and Cube Roots
Check other exercise solutions of Class 8 Maths Chapter 7 Cubes and Cube Roots
Examples From Chapter 7 Cubes and Cube Roots
| Ex.1 Find the value of 103 - 93 ? Soln: 103 - 93 = 1+(3×10×9)=1+270=271 Therefore, 1000 -729 = 271. Ex.2 Determine if 15625 is a perfect cube? Soln: By prime factorisation, 15625 = 5 × 5 × 5 × 5 × 5 × 5 ………..combining the the factors in triplets = 53 × 53 ………..by laws of exponents = (5 × 5)3 = 253 which is a perfect cube. All the terms form triplets Hence, 15625 is a perfect cube. |
Read More:
| Class 8 Chapter 7 Cubes and Cube Roots | ||
|---|---|---|
| Prime Factorization | LCM and HCF | Cubes and Cube Roots MCQs |
| Quotient | Prime Numbers | Natural Numbers |
Also Read:
| CBSE Class 8 Maths Study Guide | ||
|---|---|---|
| Maths Formula | Difference Between in Maths | Maths MCQs |
| Maths Study Notes | NCERT Solutions for Class 8 Maths | Number System |







Comments