NCERT Solutions for Class 9 Maths Chapter 4 : Linear Equations In Two Variables

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The NCERT Solutions for Class 9 Maths Chapter 4 Linear Equations In Two Variables are provided in this article. Linear equations in two variables is represented as ax + by + c = 0. When a linear equation has two variables, it is known as a linear equation in two variables. 

Class 9 Maths Chapter 4 Linear Equations In Two Variables belong to Unit 2 Algebra which has a weightage of 20 marks in the Class 9 Maths Examination. NCERT Solutions for Class 9 Maths for Chapter 4 cover the following important concepts: 

Download: NCERT Solutions for Class 9 Mathematics Chapter 4 pdf


NCERT Solutions for Class 9 Maths Chapter 4

The Chapter 4 Class 9 Maths are given below:

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Important Topics in Class 9 Maths Chapter 4 Linear Equations in Two Variables

Important Topics in Class 9 Maths Chapter 4 Linear Equations in Two Variables are elaborated below:

Introduction to Two-variable Linear Equations of the Type ax + by + c = 0

Example: Show an equation in the form of ax + by + c = 0 (Where a, b, and c are real numbers and constants.)

Solution: An equation in the form of ax + by + c = 0 can be demonstrated as:
x + 2y = 6; 2x + y = 7.

Using Bar Graph to Plot Linear Equation and Justifying any Point on a Line 

The graph of a linear equation in two variables is considered as a line. If an equation is linear, we can graph it by finding any two solutions, (x1,y1)(x1,y1) and (x2,y2)(x2,y2). After plotting these two points, we can draw the line connecting them.

Example: Given a linear function, how do can you graph plotting points? 

Solution: We can graph the plotting points:

  • First, slecet a minimum of two input values.
  • Further, calculate the required function at each input value.
  • Then use the resulting output values to recognize the coordinate pairs involved.
  • Plot the coordinate pairs on a grid.
  • Now connect the lines through the points.

Ratio and Proportion

A ratio, in linear equations, is a comparison of two given quantities. A proportion, however, is an equality of two given ratios. 

Example: Consider that ⅘ is a ratio and the proportion it has is 20/25 = ⅘. Solve and evaluate its proportional statement.

Solution: To solve its proportional statement, we have to:
20/25 = ⅘
20 x 5 = 25 x 4
100 = 100


NCERT Solutions for Class 9 Maths Chapter 4 Exercises:

The detailed solutions for all the NCERT Solutions for Linear Equations in Two Variables under different exercises are:

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CBSE X Related Questions

  • 1.
    Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$


      • 2.
        Assertion (A) : The system of linear equations $3x - 5y + 7 = 0$ and $-6x + 10y + 14 = 0$ is inconsistent.
        Reason (R) : When two linear equations don't have unique solution, they always represent parallel lines.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Assertion (A) is false, but Reason (R) is true.

        • 3.
          If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

            • $x^2 + 5x - 4$
            • $(x + 3) (-x + 8)$
            • $a(x^2 + 5x - 24)$
            • $x^2 - 24$

          • 4.
            Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

              • $\frac{5}{12}$
              • $\frac{5}{6}$
              • $1$
              • $0$

            • 5.
              PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.


                • 6.
                  Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

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