NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 Solutions are based on the Equations of Lines Parallel to the x-axis and y-axis respectively .

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Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

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Chapter Related Topics
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CBSE X Related Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.
View Solution
2.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.
View Solution
3.
The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.
View Solution
4.
The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is
- $1$
- $-5$
- $25$
- $\sqrt{5}$
View Solution
5.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is
- $\frac{5}{12}$
- $\frac{5}{6}$
- $1$
- $0$
View Solution
6.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.
View Solution

View All

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You can also check

NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.4 Solutions

Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

CBSE X Related Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

3.
The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

4.
The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

5.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

6.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

Similar Mathematics Concepts

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NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.4 Solutions

Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

CBSE X Related Questions

1.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

3.The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

4.The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

5.Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

6.A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

3.
The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.

4.
The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

5.
Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

6.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.