NCERT Solutions for Class 9 Maths Chapter 14 Statistics Exercise 14.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 14 Statistics Exercise 14.4 Solutions are based on mean, median and mode in statistics.

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Exercise Solutions of Class 9 Maths Chapter 14 Statistics

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Important Chapter Related Topics
Mean Formula Confidence Interval

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CBSE X Related Questions

  • 1.
    In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

      • $6$
      • $4$
      • $\pm 4$
      • $3$

    • 2.
      If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

        • \(4 \text{ cm}\)
        • \(4\sqrt{2} \text{ cm}\)
        • \(8 \text{ cm}\)
        • \(2\sqrt{2} \text{ cm}\)

      • 3.
        The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

          • 2
          • \(-6\)
          • \(-2\)
          • 6

        • 4.
          It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

            • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
            • \(\frac{AB}{ED} = \frac{AC}{EF}\)
            • \(\angle A = \angle D, \angle C = \angle F\)
            • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

          • 5.
            If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

              • \( -\frac{2}{3} \)
              • \( \frac{2}{3} \)
              • \( \frac{1}{3} \)
              • \( -\frac{1}{3} \)

            • 6.
              If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

                • \(\frac{7}{2}\)
                • \(\frac{6}{7}\)
                • \(\frac{-7}{6}\)
                • \(\frac{7}{6}\)

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