NCERT Solutions for Class 9 Maths Chapter 14: Statistics

Collegedunia Team logo

Collegedunia Team

Content Curator

The NCERT Solutions for class 9 Maths Chapter 14 Statistics are provided in the article below. Statistics is a mathematical body of science that pertains to the collection, analysis, interpretation and presentation of data. It also includes the mean, median and mode of ungrouped data.

Class 9 Maths Chapter 14 Statistics belong to Unit 6 Statistics and Probability which has a weightage of 6 marks in the Class 9 Maths Examination. Class 9 Mathematics Chapter 14 has the following important concepts: 

  1. Harmonic Mean Formula
  2. Confidence Interval
Download: NCERT Solutions for Class 9 Mathematics Chapter 14 pdf

NCERT Solutions for Class 9 Mathematics Chapter 14

NCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT Solutions

Important Topics in Class 9 Maths Chapter 14 Statistics

Important Topics in Class 9 Maths Chapter 14 Statistics are elaborated below:

Harmonic Mean Formula

Harmonic mean formula helps determine the multiplicative or divisor relationship between fractions without disrupting the common denominators. It is a measure of central tendency and comes under Pythagorean mean.

Example: List the steps to calculate Harmonic Mean Formula.

Solution: The steps to calculate Harmonic Mean formula for a given set of values are:

  • Step 1: First consider the reciprocal of every term in the given data set.
  • Step 2: Now, assume the count of the total number of terms whose harmonic mean needs to be calculated as ‘n’.
  • Step 3: Start adding the reciprocal terms.
  • Step 4: Finally, divide the value acquired in the 2nd step by the value acquired from the 3rd step.

Confidence Interval

The confidence level in statistics usually exhibits a frequency of confidence intervals that acomprises the true value of an unknown parameter.

Formula of Confidence Interval (CI) = \(\bar{X} ± Zα/2 × [ σ / √ n ]\)


NCERT Solutions for Class 9 Maths Chapter 14 Exercises

The detailed solutions for all the NCERT Solutions for Statistics under different exercises are:

Also Read:

Check out:

CBSE X Related Questions

  • 1.
    Assertion (A) : The system of linear equations $3x - 5y + 7 = 0$ and $-6x + 10y + 14 = 0$ is inconsistent.
    Reason (R) : When two linear equations don't have unique solution, they always represent parallel lines.

      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Assertion (A) is false, but Reason (R) is true.

    • 2.
      In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.


        • 3.
          The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.


            • 4.
              A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.


                • 5.
                  Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.


                    • 6.
                      Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

                        Comments


                        No Comments To Show