NCERT Solutions for Class 9 Maths Chapter 8 Triangles Exercise 8.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.1 Solutions are based on different types of quadrilaterals, and their properties.

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Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

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CBSE X Related Questions

  • 1.
    In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

      • \( 130^\circ \)
      • \( 50^\circ \)
      • \( 120^\circ \)
      • \( 90^\circ \)

    • 2.
      The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

        • 0
        • 1
        • 3
        • 2

      • 3.
        PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


          • 4.
            If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

              • \(4 \text{ cm}\)
              • \(4\sqrt{2} \text{ cm}\)
              • \(8 \text{ cm}\)
              • \(2\sqrt{2} \text{ cm}\)

            • 5.
              In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

                • \(2.5\) cm
                • \(10.5\) cm
                • \(3.5\) cm
                • \(\frac{14}{3}\) cm

              • 6.
                If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).

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