NCERT Solutions for Class 9 Maths Chapter 8 Triangles Exercise 8.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.2 Solutions are based on the Mid-point Theorem.

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Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

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CBSE X Related Questions

  • 1.
    It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

      • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
      • \(\frac{AB}{ED} = \frac{AC}{EF}\)
      • \(\angle A = \angle D, \angle C = \angle F\)
      • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

    • 2.
      If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

        • \(4 \text{ cm}\)
        • \(4\sqrt{2} \text{ cm}\)
        • \(8 \text{ cm}\)
        • \(2\sqrt{2} \text{ cm}\)

      • 3.
        Which of the following graphs represents a polynomial with both zeroes being positive?


        • 4.
          There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

            • 144
            • 2
            • 420
            • 272

          • 5.
            If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

              • \( -\frac{2}{3} \)
              • \( \frac{2}{3} \)
              • \( \frac{1}{3} \)
              • \( -\frac{1}{3} \)

            • 6.
              If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

                • \(\frac{7}{2}\)
                • \(\frac{6}{7}\)
                • \(\frac{-7}{6}\)
                • \(\frac{7}{6}\)

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