NCERT Solutions for Class 9 Maths Chapter 8 Triangles Exercise 8.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 8 Quadrilaterals Exercise 8.2 Solutions are based on the Mid-point Theorem.

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Exercise Solutions of Class 9 Maths Chapter 8 Quadrilaterals

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CBSE X Related Questions

  • 1.
    For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

      • \(0\)
      • \(\frac{80}{81}\)
      • \(1\)
      • \(\frac{82}{80}\)

    • 2.
      There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

        • 144
        • 2
        • 420
        • 272

      • 3.
        Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

          • \(10^{\circ}\)
          • \(60^{\circ}\)
          • \(45^{\circ}\)
          • \(100^{\circ}\)

        • 4.
          If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

            • \( -\frac{2}{3} \)
            • \( \frac{2}{3} \)
            • \( \frac{1}{3} \)
            • \( -\frac{1}{3} \)

          • 5.
            The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

              • 2
              • \(-6\)
              • \(-2\)
              • 6

            • 6.
              In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

                • $6$
                • $4$
                • $\pm 4$
                • $3$

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