Regular Tetrahedron Formula: Definition, Properties, Area & Solved Examples

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Jasmine Grover

Education Journalist | Study Abroad Lead

Tetrahedron is an interesting three-dimensional figure with four triangular faces and has six straight edges, and four vertex corners. One of the triangles is considered the base and the other three triangles together form a pyramid. For ease of visualization, you can think of it as a triangular pyramid. A tetrahedron is a type of pyramid, a polyhedron with a flat polygonal base and triangular faces connecting the bases and common points. It can be also called a triangular pyramid because its base is a triangle. Elaborated below are the various tetrahedral formulas related to surface area and volume in detail in order to understand the meaning of the symbols used in each formula.

Key Terms: Tetrahedron, Three-dimensional Figures, Triangle, Pyramid, Polyhedron, Surface Area, Lateral Surface Area, Vertices, Interior Angles


What is Tetrahedron?

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A tetrahedron is a polyhedron with 4 faces, 6 sides, and 4 vertices, all of which are triangles. It can also be called a triangular pyramid whose base is also a triangle. An equilateral tetrahedron has equilateral triangles so all its interior angles are equal to 60°. Since each plane in a tetrahedron is a triangle, thus, the interior angles of a tetrahedron in each plane add up to 180°.

Tetrahedron

Tetrahedron


Properties of Tetrahedron

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A tetrahedron is a three-dimensional shape that features several different properties. The below mentioned are the characteristics of the tetrahedron that make it easy to identify the shape.

  • There are 4 faces, 6 edges, and 4 vertices (corners).
  • A regular tetrahedron has all four corners equidistant from each other. There are 6 planes of symmetry.
  • Unlike other regular polyhedra, there are no parallel faces.
  • A regular tetrahedron has four equilateral triangles as faces.

Faces and Edges of a Tetrahedron

Faces and Edges of a Tetrahedron

Read More: Area of Equilateral Triangle


Surface Area of Tetrahedron

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The surface area of a tetrahedron is defined as the total area or area covered by all faces of the shape. It is expressed in squares such as m2, cm2, ft2, yd2. A tetrahedron has two types of surface area namely the Lateral Surface Area of Tetrahedron and the Total Surface Area of Tetrahedron.

  • Lateral Surface Area of Tetrahedron

The lateral face of a tetrahedron is defined as the surface of the lateral or slant faces of the tetrahedron. The formula for the area of the sides of a regular tetrahedron is given by,

Lateral Surface Area of Regular Tetrahedron = Sum of 3 congruent equilateral triangles, i.e. lateral faces) = 3 × (√3)/4 a2 square units

Here ‘a’ denotes the side length of a regular tetrahedron.

Read More: Edges, Faces, and Vertices

  • Total Surface Area of Tetrahedron

The total area of a tetrahedron is defined as the area of all the faces of a tetrahedron. The formula for the total area of a regular tetrahedron is given by,

Total Surface Area of Equilateral Quadrilateral = Sum of 4 congruent equilateral triangles (i.e. side faces) = 4 × (√3) / 4 a2 = √3 a2 square units.

Here ‘a’ denotes the length of the side of the regular tetrahedron


Volume of Tetrahedron

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The volume of a tetrahedron is defined as the total space it occupies in a three-dimensional plane. The formula for the volume of a tetrahedron is given by,

Volume of a regular tetrahedron = (1/3) × base area × height = (1/3) (√3) / 4 a2 × (√2) / (√3) a = (√2 / 12) a3 cubic units.

Here ‘a’ is the lengths of the sides of a regular tetrahedron

Tetrahedron Figure

Tetrahedron Figure

Read More: Difference between Area and Volume


Things to Remember

  • A tetrahedron is a triangular pyramid with all four sides triangular.
  • Basically, a tetrahedron has 4 faces, 6 edges, and 4 vertex corners.
  • A tetrahedron can be drawn using a geometric net as it has a 3D shape.
  • A tetrahedron is made up of 4 triangular faces, that’s why its base is considered a triangle.
  • Michigan artist David Barr developed the Four Corners project in 1976. A typical Earth-sized tetrahedron crosses the planet with only the four corners protruding at the tips.
  • The total surface area of a tetrahedron is √3 a2 square units while the lateral surface area is 3 × (√3)/4 a2 square units.
  • The volume of a tetrahedron is given by the formula (√2 / 12) a3 cubic units.

Solved Questions

Ques. What is the volume of a tetrahedron with sides of 25 cm? (3 Marks)

Ans. Here, a = 25 cm

Let’s use the formula of Volume of a Regular Tetrahedron: (√2 / 12) a3

= (√2 / 12) 253

= 1,841.4 cm3

Ques. What is the volume of a Regular Tetrahedron, if its Total Surface Area is 36√3 cm? (5 Marks)

Ans.Here, TSA of Tetrahedron: 36√3 cm

Let's first find out the side of the tetrahedron.

Using the formulae of TSA of Tetrahedron = √3 a2

Now putting the TSA of Tetrahedron = √3 a2

36√3 = √3 a2

36√3 / √3 = a2

36 = a2

Hence a = 6,

Now Using the formulae of Volume of Regular Tetrahedron = (√2 / 12) a3

= (√2 / 12) 63 = 25.45 cm3

Ques. A tetrahedron has four faces and six edges. How many vertices will it have? (3 Marks)

Ans.A tetrahedron will have 4 vertices.

We know that V−E+F=2

Here V, E, F denotes

V= no. of vertices =?

E= no. of edges =6

F= no. of faces =4

V−6+4=2

V−2=2

V=4

Ques. How many vertices and edges does the truncated tetrahedron have? (3 Marks)

Ans.A truncated tetrahedron has 12 vertices and 18 edges in total. A truncated tetrahedron has 4 regular hexagonal faces, 4 equilateral triangle faces, 12 vertices, and 18 edges (of two types). You can construct it by truncating all 4 vertices of a regular tetrahedron at one-third of the original edge length.

Ques. Find out the edge of the tetrahedron if its volume is 1/3? (3 Marks)

Ans.Using the formulae to find out the edge of a tetrahedron,

e = √23√3V

Substituting the volume and solving.

e = √23√3( 1/3)

e = √23√1

e = √2

The edge of the tetrahedron will be √2.

Ques. Find out the edge of the tetrahedron if its volume is 9 cm3? (3 Marks)

Ans.Using the formulae to find out the edge of a tetrahedron,

e = √23√3V

Substituting the volume and solving.

e = √23√3(9)

e = √23√27

e = 3√2

The edge of the tetrahedron will be 3√2.

Ques. Find out the total surface area of a tetrahedron, the edge of a tetrahedron is 12 cm? (3 Marks)

Ans.Using the formulae of the total surface area of tetrahedron= √3a2

Here ‘a’ denotes the edge of the tetrahedron.

= √3(122) = 249.4 cm2

The total surface area of the tetrahedron will be 249.4 cm2.

Ques. Find out the lateral surface area of tetrahedron if its volume is 18√3cm3? (3 Marks)

Ans. Let ‘a’ be the edge of the tetrahedron.

Firstly, we will be using the formulae of the volume of tetrahedron = (√2 / 12) a2

18√3 = (√2 / 12) a3 [Putting the given volume of a tetrahedron to find out the edge of the tetrahedron.]

216 = a3

a = 6 cm

Using the formulae of Lateral Surface Area of Tetrahedron = 3 × (√3)/4 a2

= 3 × (√3)/4 (62)

= 27√3 cm2

The lateral surface area of the tetrahedron will be 27√3cm3.

Ques. The surface area of a regular tetrahedron is 156 cm2, find the length of an edge of a regular tetrahedron? (3 Marks)

Ans. Given SA = 156 cm2, Let ‘a’ be the length of an edge.

Using the formulae of SA = √3 a2

(Putting the value of SA) 156 = √3 a2

√156√3 = a

a = 9.5 cm

The length of an edge of a regular tetrahedron would be 9.5 cm.

Ques. Find the volume of the regular tetrahedron if its edge is 9.3 m? (3 Marks)

Ans. Given the edge of regular tetrahedron = 9.3 m

Using the formula of Volume of regular tetrahedron = (√2 / 12) a3

=(√2/12) 9.33

= (0.11785) 9.33

= 94.79 m3

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CBSE X Related Questions

  • 1.
    If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

      • 3
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    • 2.
      Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
      Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

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      • 3.
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          • 4.
            A kite is flying at a height of \(60 \text{ m}\) above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as \(30^{\circ}\). From the bottom of the same building, the angle of elevation of kite is \(45^{\circ}\). Find the length of the string and height of roof from the ground. (Use \(\sqrt{3} = 1.73\))


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