Straight Angle: Measurement, Construction, Properties & Theorems

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Straight angle is an angle with the sides opposite to the vertex in the same straight line that equals two right angles. A straight angle measures 180° (half a revolution, two right angles, or π radians). The angles form a straight line that passes through the vertex. A straight angle is also known as a 'flat angle.'

Key Takeaways: Straight angle, Angle, Liens, Straight lines, Vertex, Line segments

Also read: Isosceles Triangle Theorems


Straight Angle Measurement

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A straight angle is similar to a straight line and has an angle measurement greater than an obtuse angle. The measurement of 180° creates a straight angle between the two intersecting lines. Straight angles can be formed by connecting three points on any straight line, each of which has a coordinate value. The outside points are the endpoints of two line segments, and the middle point is the vertex where these two lines intersect at an angle of 180°.

Straight Angle

Straight Angle

The video below explains this:

Straight Angle Detailed Video Explanation:


Properties of Straight Angles

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Straight angles have the following important properties:

  • Both sides of a straight angle are perpendicular to each other.
  • Half of the rotation is completed by the straight angle.
  • The degree of straightness is 1800.
  • Straight angles can be created by joining two right angles together.

Also read: Collinear points


Straight Angle Theorems

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According to the straight angle theorem, all straight angles are 180 degrees. A straight angle is formed when the legs of an angle point exactly in opposite directions. A straight angle is denoted by the symbol 180 (in degrees) or (in radians).

In geometry, one good example is a line segment, the endpoints of which extend in the opposite direction.


Construction of Straight Angle

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The steps for making a Straight Angle are as follows:

  • Using a ruler, draw a straight line OB with an arrowhead at B.
  • Place the protractor on this line so that the protractor's baseline is adjusted over OB. Point B should be oriented towards the protractor's 0°.
  • Mark the point starting at 0° and working your way up to 180°. When you reach 180°, make a mark on the paper with the letter A.
  • Now connect the vertex of the OB line to the marked point A. The arrowhead on the second ray OA should be at A.

Also read: Minors and Cofactors


Things to Remember

  • Straight angles appear to be straight lines, but they have two arms. A straight line, on the other hand, has only one arm that points in one direction.
  • When the sum of an acute angle and an obtuse angle is equal to a straight angle, those angles are considered supplementary.
  • When we look at the angles within a circumference, we can see that they divide the circle into two equal halves and correspond to the circumference's diameter.
  • It is the boundary between convex (acute, right, and obtuse angles) and concave angles.
  • When you stretch your arms or a dancer stretches their legs you can see straight angles.

Also read: Properties of Determinants


Sample Questions

Ques: Find the value of angle C in ∠ABC where ∠ A=25°and ∠B=90° (3 marks)

Ans: Given ∠ A=25°and ∠B=90°

We know that, 

The sum of interior angles of a triangle is 180°

Thus, ∠A+ ∠B+∠C = 180°

or, 25°+ 90° + ∠C = 180°

Or, ∠C = 180°- 115°

or, ∠C= 65°

Ques: Find the value of angle D in a Quadrilateral ABCD, where∠ A=100°, ∠B=60° and ∠C=35° (3 marks)

Ans: ∠A= 100°

∠B=60°

∠C= 35° 

Here, we need to find the value of D

Therefore, 

∠ A+∠B+∠C+∠D= 360°

Or, 100°+60°+35°= 360°

Or, 195°+ ∠D = 360°

Or, ∠D= 165°

Ques: ∠AOB is a straight angle, ∠AOC = (3x+20)° and ∠ BOC =(4 x-36)°. Find the value of the x. (3 marks)

Ans: As given that∠ AOC = (3x + 20)° and ∠BOC = (4x- 36) °and AOB is a straight angle.

We know that straight angle measures 180°

Therefore,

∠AOB= ∠AOC +∠BOC

180° = (3x+20)°+ (4x- 36)°

180°= 7x-16

7x= 196°

x= 28°

Ques: Find the angle complementary to the angle 50°. (3 marks)

Ans: The given angle is 50°

Here, we need to find the complementary of it

We know that two angles are complementary when they add up to 90°

Let the complementary angle be x

Now

x= 90°-50°=40°

Ques: find the supplementary of the angle 120° (2 marks)

Ans: The given angle is 120°

Here , we need to find the supplementary of it, 

Let supplementary angle be x,

x= 180°-120°=60°

Ques: ∠AOB is a straight angle, ∠AOC = 68°, and ∠BOC= x°. Find the value of the x. (2 marks)

Ans: As given that ∠AOC =68° AND ∠AOB is a straight angle

We know that straight angle measures 180°

Therefore, 

180°=68°+x

x=112°

Ques: The difference between the two complementary angles is 180°. Find the measure of the angle. (3 marks)

Ans: Let one angle be of measure x°,

Then complement of x= (90-x)°

difference= 18°

Therefore,(90-x)°-x° =18°

Or, 90°-90°-2x= 18°-90°

Or, x=72/2

x= 36°

Also, 90°-x= 54°

Therefore the two angles are 36° and 54°

Ques: The measure of two supplementary angles are (3x + 15)° and (2x + 5)°. Find the value of x. (3 marks)

Ans: According to the problem (3x-15)° and (2x-5)° are complementary

(3x-15)° + (2x+5)° = 180°

Or, 3x+15+2x+5= 180°

Or, 5x+20°= 180°

Or, 5x= 160/5

x= 32°

Also Read:

CBSE X Related Questions

  • 1.
    Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)


      • 2.
        If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


          • 3.
            The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

              • 0
              • 1
              • 3
              • 2

            • 4.
              There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

                • 144
                • 2
                • 420
                • 272

              • 5.
                In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

                  • \(2.5\) cm
                  • \(10.5\) cm
                  • \(3.5\) cm
                  • \(\frac{14}{3}\) cm

                • 6.
                  The HCF of 960 and 432 is :

                    • 48
                    • 54
                    • 72
                    • 36

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