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Mensuration is responsible for dealing with concepts of lengths, areas and volumes, when it comes to two-dimensional and three-dimensional shapes. Mensuration defines principles of calculation and important equations and properties of geometric shapes and figures. Menstruation formula is applicable in solving real-life problems.
Ques 1. Find the area of a rhombus whose diagonals are given to be of lengths 6 cm and 7 cm.
- 30 cm2
- 21 cm2
- 28 cm2
- 42 cm2
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Answer: b) 21 cm2
Explanation: Since the area of a rhombus is given to be
Area = ½ X (product of lengths of the diagonals)
Therefore,
area = ½ X (6 X 7) cm2
= 21 cm2
Ques 2. Find the radius of a circle whose circumference is given to be 95 cm (take pi= 3.14).
- 18.32 cm
- 14.91 cm
- 15.13 cm
- 15.41 cm
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Answer: c) 15.13 cm
Explanation: We know that the circumference for a circle is given as,
C= 2πr
Substituting the values given in the question, we get
r = 95/ (2 X 3.14) cm
Hence, giving us,
r = 15.13 cm
Ques 3. Find the length of the edge of a cube whose surface area is given as 54 cm².
- 6 cm
- 9 cm
- 3 cm
- 12 cm
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Answer: c) 3 cm
Explanation: The surface area for a cube is given as
A = 6 (edge)2.
Therefore, upon substituting the value for surface area in the above formula,
(edge)² = 54/ 6 cm2
= 9 cm2
After taking the square root, we get,
edge = 3 cm
Ques 4. What is the formula for the curved surface area of a regular cylinder?
- πrh
- πr2
- πr2h
- 2πrh
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Answer: d) 2πrh
Explanation: The formula for the curved surface area of a regular cylinder is 2πrh
Ques 5. Find the breadth of a cuboid when the volume is given to be 64 m³ for length and height given as 8 m and 2 m, respectively.
- 8 m
- 2 m
- 4 m
- 6 m
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Answer: c) 4 m
Explanation: The volume for a cuboid is given as,
vol = length x breadth x height
Substituting the above-given values and rearranging the equation gives us
breadth = 64/ (8 x 2) m
= 4 m
Ques 6. Find the diameter of the circle whose area is given to be 113.04 m2 (take pi = 3.14)
- 12 m
- 36 m
- 6 m
- 24 m
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Answer: a) 12m
Explanation: The area for a circle is known to be,
area= π r2
And the diameter for a circle is known to be,
d = 2 x r
Using the above two equations and substituting the values given in the question,
113.04 = 3.14 x r2
r² = 113.04/ 3.14 m2
r = 6 m
Hence,
d = 2 x r
Gives us,
d = 2 x 6 m
= 12 m
Ques 7. Find the area of a parallelogram with height and breadth given to be 11 cm and 12 cm, respectively.
- 66 cm2
- 132 cm2
- 144 cm2
- 121 cm2
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Answer: b) 132 cm2
Explanation: The formula for the area of a parallelogram is given as
area = base x height
Upon substituting the values for breadth and height, we get
area = 11 x 12 cm2
= 132 cm2
Ques 8. What is the area of a triangle whose base is given to be 7 cm and height as 8 cm?
- 56 cm2
- 28 cm2
- 23 cm2
- 21 cm2
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Answer: b) 28 cm2
Explanation: We know that the formula for the area of a triangle is,
area = ½ x base x height
Substituting the values for the base and height, we get,
area = ½ x 7 x 3 cm2
= 28 cm2
Ques 9. Find the height of a regular cylinder whose radius is 14 cm and the total surface area is 4342 cm² is (take pi= 22/7):
- 33.61 cm
- 29.45 cm
- 35.34 cm
- 39.41 cm
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Answer: d) 39.41
Explanation: For a given cylinder, we know that
Total surface area = 2πr (h + r)
Therefore,
4342= 2 x 22/7 x 14 (h + 14) cm²2
h = 35.34 cm
Ques 10. Find the perimeter of the largest circle that can fit inside a square with the side 7cm (take pi = 22/7).
- 14 cm
- 24 cm
- 28 cm
- 22 cm
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Answer: d) 22 cm
Explanation: Given, that the side of the square is 7cm
Hence, the diameter of the largest circle to fit inside the square, d = 7 cm
This implies that radius, r = 7/2 cm = 3.5 cm
Using the formula for circumference,
C = 2πr
We get,
C = 2 x 22/7 x 3.5 cm
= 22 cm
Ques 11. The number of pairs of identical faces in a cuboid.
- 3
- 4
- 2
- 5
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Answer: a) 3
Explanation: A cuboid comprises rectangles. Of the 6 faces, only 2 will be identical (i.e. present in pairs of l x b, b x h, h x l)
Ques 12. The area of a rhombus is 360 cm² and one of the diagonals is 12 cm. Find the other diagonal.
- 42 cm
- 60 cm
- 72 cm
- 54 cm
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Answer: b) 60 cm
Explanation: Because the area of a rhombus is given as,
area = ½ X (product of lengths of the diagonals)
Therefore, we get,
360 = ½ X (12 x diagonal2) cm2
diagonal2 = 60 cm
Ques 13. A cuboidal box has its length, breadth and height given to be 10 cm, 5 cm and 15 cm, respectively. Find the total surface area for the cuboid
- 1000 cm2
- 600 cm2
- 550 cm2
- 800 cm2
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Answer: c) 550 cm2
Explanation: The formula for total surface area for a cuboid is given as
TSA = 2 x [(l × b) + (b × h) + (h × l)]
Hence, upon substituting the values for length, breadth and height,
TSA = 2 x [(10 x 5)+ (5 x 15) + (15 x 10)]
= 1300 cm2
Ques 14. Find the total surface area for a cube whose volume is given to be 512 m³.
- 384 cm2
- 644 cm2
- 586 cm2
- 822 cm2
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Answer: a) 384 cm2
Explanation: The volume for a cube is known to be
vol = edge x edge x edge
This implies,
512 = (edge)3. m3
Therefore,
edge = 8 m
Since, the total surface area for a cube is known to be
total surface area = 6 x (edge)2
Upon solving for the square root, we get,
TSA = 384 cm2
Ques 15. The area of a trapezium is 1240 m2. The distance between the two pairs of parallel sides is given to be 20 m. If the length of one of the parallel sides is 60 m, find the length of the other parallel side.
- 68 m
- 54 m
- 64 m
- 70 m
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Answer: c) 64 m
Explanation: Using the formula for the area of a trapezium, we get
Area = ½ h (a+b)
Upon substituting the values given in the above question,
1240 = ½ x 20 x (60+b) m2
Solving the above equation for b gives us,
b = 64 m
Ques 16. 1litre = ______ cubic centimeters?
- 10 cm3
- 10000 cm3
- 100 cm3
- 1000 cm3
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Answer: d) 1000 cm3
Explanation: The conversion ratio from cubic meter to litres is
1 m3 = 1,000 l
Since 1 m3 = 1000000 cm3
Using the above two conversion ratios, we get
1 l = 1000 cm3
Ques 17. How many cubes with an edge length of 2 cm can fit inside a cuboid with dimensions of length, breadth and height given to be 8 m, 6 m, and 10 m, respectively?
- 60000
- 60000000
- 600000
- 6000
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Answer: b) 60000000
Explanation: Before we calculate the volume of the cuboid, we convert the length, breadth and height into mm from (using the conversion 1 m = 100 cm)
Therefore,
l = 800 cm
b = 600 cm
h = 1000 cm
Using the formula
vol = l x b x h
We get the volume of the cuboid as 480000000 cm3
The volume of one of the small cubes is 8 cm3 (using the formula edge x edge x edge)
Hence, the total number of cubes that can fit inside the cuboid is calculated as
tot no. of cubes = 480000000/8
= 60000000
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