NCERT Solutions Class 11 Maths Chapter 1 Sets Exercise 1.1 Solutions

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Class 11 Maths NCERT Solutions Chapter 1 Sets Exercise 1.1 cover following concepts: Introduction to sets and Sets and their Representations.

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Also Read:

Chapter 1 Sets Important Topics
Types of Sets	De Morgan’s Laws	Set Theory Symbols
Set Formulas	Number Theory	Group Theory
Universal Set	What is disjoint set	Equal equivalent sets

Also Read:

CBSE Class 11 Mathematics Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
For a square matrix \(A\), \[ (3A)^{-1}= \]
- \( 3A^{-1} \)
- \( 9A^{-1} \)
- \( \frac{1}{3} A^{-1} \)
- \( \frac{1}{9} A^{-1} \)
View Solution
2.
Evaluate: \[ \cos\left[\sin^{-1}(-1)-\tan^{-1}(-\sqrt{3})\right]. \]
View Solution
3.
The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:
- \( e^{-3} \)
- \( -1 \)
- \( 1 \)
- \( -e^3 \)
View Solution
4.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.
View Solution
5.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]
View Solution
6.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.
View Solution

Similar Mathematics Concepts

Types of Sets: What is Set, Examples & Symbols

Universal Set: Definition, Symbol, Complement & Examples

What is a Set? Types, Properties & Examples

Set Theory: Types, Representation, Symbols, Formulas

Class 11 Maths NCERT Solutions Chapter 1 Sets

Set Theory Symbols: Types, Set Operations & Examples

Sets Important Questions: Detailed Solutions & Explanation

NCERT Solutions Class 11 Maths Chapter 1 Sets Exercise 1.2 Solutions

NCERT Solutions Class 11 Maths Chapter 1 Sets Exercise 1.3 Solutions

NCERT Solutions Class 11 Maths Chapter 1 Sets Exercise 1.4 Solutions

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