NCERT Solutions for Class 11 Maths Chapter 14 Exercise 14.1

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Class 11 Maths NCERT Solutions Chapter 14 Mathematical Reasoning Exercise 14.1 are based on the following concepts:

Statements
New statements from old
Special words / Phrases
Implications
Validating Statements
Conjunction

Download PDF NCERT Solutions for Class 11 Chapter 14 Mathematical Reasoning Exercise 14.1

Check out the solutions of Class 11 Maths NCERT Solutions Chapter 14 Mathematical Reasoning Exercise 14.1

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Also check other Exercise Solutions of Class 11 Maths Chapter 14 Mathematical Reasoning

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Chapter Related Topics
Irrational Number	Prime Number	Real Number

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Difference Between Topics in Maths	Math Study Material	Arithmetic

CBSE CLASS XII Related Questions

1.
In a school, the probability of holding a debate competition is \( \frac{1}{3} \) and that of a quiz competition is \( \frac{2}{3} \). In the two participating teams, A has 4 girls and 6 boys and B has 7 girls and 3 boys. If a debate competition is held, the students are selected from team A and for the quiz competition they are selected from team B. If only two students are to be chosen from the teams, then find the probability that one will be a girl and the other a boy.
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2.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]
View Solution
3.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.
View Solution
4.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:
- \([-1, 1]\)
- \([4, 6]\)
- \([-7, -3]\)
- \([2, 3]\)
View Solution
5.
Sports car racing is a form of motorsport which uses sports car prototypes.The competition is held on special tracks designed in various shapes.
The equation of a sports car racing track is given as: \[ f(x)= \begin{cases} x^4-4x^2+4, & 0\leq x<3,\\ x^2+40, & x\geq 3 \end{cases} \] Based on this information:
6.
Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true and Reason (R) is false.
- Assertion (A) is false and Reason (R) is true.
View Solution

Similar Mathematics Concepts

NCERT Solutions for Class 11 Maths Chapter 14: Mathematical Reasoning

Important Questions for Class 11 Maths Chapter 14 Mathematical Reasoning

NCERT Solutions for Class 11 Maths Chapter 14 Exercise 14.2

NCERT Solutions for Class 11 Maths Chapter 14 Exercise 14.3

NCERT Solutions for Class 11 Maths Chapter 14 Exercise 14.4

NCERT Solutions for Class 11 Maths Chapter 14 Exercise 14.5

NCERT Solutions for Class 11 Maths Chapter 14 Miscellaneous Exercises

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