NCERT Solutions for Class 11 Maths Chapter 14 Exercise 14.4

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Class 11 Maths NCERT Solutions Chapter 14 Mathematical Reasoning Exercise 14.4 are based on the following concepts: 

  • New statements from old statements
  • Implications
  • Validating Statements
  • Conjunction

Download PDF NCERT Solutions for Class 11 Chapter 14 Mathematical Reasoning Exercise 14.4

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Chapter Related Topics
Irrational Number Prime Number Real Number

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CBSE CLASS XII Related Questions

  • 1.
    Find:

    If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

      • \(0\)
      • \(-2\)
      • \(-1\)
      • \(2\)

    • 2.

      A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 


        • 3.
          Which of the following equations is NOT a Linear Differential Equation?

            • \((1 + x^2) \, dy + 2xy \, dx = \cot x \, dx\)
            • \(y + \frac{d}{dx}(xy) = x(\sin x + \log x)\)
            • \(x(1 + y^2) \, dx - y(1 + x^2) \, dy = 0\)
            • \(y \, dx - (x + 3y^2) \, dy = 0\)

          • 4.

            Evaluate:
            \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


              • 5.
                A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is

                  • Reflexive only
                  • Reflexive and Transitive
                  • Symmetric and Transitive
                  • Symmetric only

                • 6.

                  Find:
                  Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

                    • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
                    • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
                    • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
                    • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
                  CBSE CLASS XII Previous Year Papers

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