NCERT Solutions for class 7 Mathematics Chapter 13 : Exponents and Powers

NCERT Solutions for class 7 Mathematics Chapter 13 Exponents and Powers are provided in the article below. Exponent is generally defined as a positive or negative number that represents the power to which the base number is to be raised. In mathematics, the term Power refers to the repeated multiplication of the same integer. The power of a number specifies how many times that number should be multiplied.

Download: NCERT Solutions for Class 7 Mathematics Chapter 13 pdf

NCERT Solutions for Class 7 Mathematics Chapter 13

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers is given below.

Class 7 Maths Chapter 13 Exponents & Powers – Important Topics

Power: Power denotes the amount of time a number has to be multiplied by itself.

Exponent: Exponent is generally defined as a positive or negative number that represents the power to which the base number is to be raised.

Some of the rules of exponents include:

x⁰ = 1
(x^m)ⁿ = x^mn
x^m × y^m = (xy)^m
x^m ÷ y^m = (x/y)^m
x^m × xⁿ = x^m+n
x^m ÷ xⁿ = x^m-n

NCERT Solutions for Class 7 Maths Chapter 13 Exercises

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers Exercises are given below.

Read More:

Scientific Notation Formula	Exponential Formula
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NCERT Solutions for Class 7 Maths	Number System	Geometry
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CBSE X Related Questions

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?
- 144
- 2
- 420
- 272
View Solution
2.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.
View Solution
3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.
View Solution
4.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- \( 130^\circ \)
- \( 50^\circ \)
- \( 120^\circ \)
- \( 90^\circ \)
View Solution
5.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution
6.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)
View Solution

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NCERT Solutions for class 7 Mathematics Chapter 13 : Exponents and Powers

Download: NCERT Solutions for Class 7 Mathematics Chapter 13 pdf

NCERT Solutions for Class 7 Mathematics Chapter 13

Class 7 Maths Chapter 13 Exponents & Powers – Important Topics

NCERT Solutions for Class 7 Maths Chapter 13 Exercises

CBSE X Related Questions

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

4.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

5.
The HCF of 960 and 432 is :

6.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

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NCERT Solutions for class 7 Mathematics Chapter 13 : Exponents and Powers

​Download: NCERT Solutions for Class 7 Mathematics Chapter 13 pdf

NCERT Solutions for Class 7 Mathematics Chapter 13

Class 7 Maths Chapter 13 Exponents & Powers – Important Topics

NCERT Solutions for Class 7 Maths Chapter 13 Exercises

CBSE X Related Questions

1.There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

3.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

4.In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

5.The HCF of 960 and 432 is :

6.Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

Comments

SUBSCRIBE TO OUR NEWS LETTER

Download: NCERT Solutions for Class 7 Mathematics Chapter 13 pdf

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.
In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

3.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.

4.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

5.
The HCF of 960 and 432 is :

6.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)