Introduction, Angles, Diagonals, Properties, Formula & Solved Questions

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A hexagon which is an equilateral as well as an equiangular is called a Regular hexagon. A Regular hexagon is bi-centric, which indicates that it’s both; cyclic and tangential i.e., it has an inscribed circle & a circumscribed circle. 

It is a 6-side polygon different from an irregular hexagon. A Regular hexagon consist six rotational symmetries along with six reflection symmetries i.e., all six sides & edges of hexagon are equal.

Check Solution for Class 8 Chapter 3 Understanding Quadrilaterals


What is Regular Hexagon?

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A regular hexagon is a polygon;

  • Have six equal sides, which means having equal six sides mean all equal angles,
  • “Hex” means six which represent sides, i.e., six sides shape,
  • Lengths & measurement of all the sides are equal & it has a convex geometrical shape,
  • All the points of a regular hexagon point outwards,
  • There are total 9 diagonals,
  • The sum of all interior angles will be 720 degrees & exterior angles will be 360 degrees, 
  • Each interior angle will be 120 degrees, & each exterior angle will be 60 degrees,
  • The area will be the region occupied by hexagon inside its boundary,
  • The perimeter of hexagon will be the total length of all 6 sides,
  • The triangles formed by joining the centre with all the vertices, are equal in size and are equilateral.

Check Important Difference Between Square and Rhombus


How to draw a Regular Hexagon?

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A regular hexagon is easy to draw. One only need compass, rules & pen/pencil & should follow the steps below;

  1. Draw a linear segment whose length will be the hexagon side length,
  2. Construct a circle, its centre should be at one end of the linear segment and radius should be equal to the segment length,
  3. A second circle should be constructed without changing the radius, & its centre should be at the other end of the linear segment. The two points are defined where this circle intersects with the first one.
  4. With the help of the same radius, construct a new circle placing the tip of the compass on the last defined point,
  5. A new point will be defined as it intersects with the first circle.
  6. Repeat this procedure for two more times i.e., Place the tip of the compass on the last point and construct another circle,
  7. There will be a total of six points around the first circle,
  8. These points will become the vertices of the hexagon,
  9. At last, Draw linear segments between them,
  10. Regular hexagon is created.
Regular Hexagon
Regular Hexagon
Check Important Notes for Properties of Hexagon

Angles of the regular hexagon

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  • The sum of all the angles of a regular hexagon is equal to 720,
  • There are total six sides in a regular hexagon,
  • The sum of interior angles of a regular hexagon = (6-2) x 180 degrees = 720 degrees,
  • The value of an interior angle of the regular hexagon is = 720/6 degrees =120 degrees,
  • The central angle of the regular hexagon measures: 360:6 degrees =60 degrees.

Diagonals of the Regular Hexagon

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  • A diagonal is known as a line that joins two non-adjacent vertices. A regular hexagon has a total of 9 diagonals,
  • The total number of diagonals = 6 x (6-3): 2 = 9

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Formulas for the Regular Hexagon

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1] Area of a Regular Hexagon-

Divide the regular hexagon into small six isosceles triangles. Then find the area of the triangles one by one multiply it by 6 to find the total area of the polygon.

FORMULA: 

A = 3(√3/2)a2

Three different ways to find out the area are as follows:

  1. When the length of the side of a regular hexagon is given, the formula will be:

Area = s²n/4 tan (180/n)

Where, s = length of the side & n = number of the side.

  1. When the radius (circumradius) is given, the formula will be:

Area = r²n sin (360/n)/2

Where, r = radius (circumradius) & n = number of the side

  1. When the apothem (in radius) is given, the formula will be:

Area = a²n tan (180/n)

Where, a = length of the apothem & n = number of the side

2] Perimeter of a Regular Hexagon-

It can be determined by calculating the sum of all the six sides of a regular hexagon. The perimeter will be the sum of all 6 side lengths of the hexagon. The perimeter of a hexagon is given by:

FORMULA: 

P = 6a

Where, a = sides of regular hexagon.

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Things to Remember

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  • It has 6 vertices with 6 equal sides and 6 equal angles,
  • It constitutes of six equilateral triangles,
  • The hexagon’s radius is equal to the length of its sides,
  • The interior angles are 120° of regular hexagon,
  • The exterior angles of a regular hexagon are 60°,
  • Sum of interior angle is 720°,
  • A regular Hexagon has 9 diagonals.
  • All the sides opposite to each other are parallel in nature.

Check Also: Quadrilateral Angle Sum Property


Sample Questions

Question 1: What will be the Area of a Regular Hexagon with an in radius of 10√3? (1 mark)

Answer: Area = 1/2pa

= ½ x 120 x 10√3

= 600√3 units²

Explanation; Where ‘P’ stands for perimeter & ‘a’ is the sides. So, we first we have to find the perimeter of the hexagon. By using the apothem to find the perimeter of the hexagon. The perimeter will be 120.

Question 2: What are the Real-life Examples of a Hexagon? (1 mark)

Answer: Real-life examples of a hexagon can be the cells in the beehives or the outer part of a metal nut. There are white and black shapes of a hexagon on the football

Question 3: How to Find the Area of an Irregular Hexagon? (2 marks)

Answer: An irregular hexagon has different sides and angles thus, finding the area of an irregular hexagon differs from the way we find the area of a regular hexagon. In order to find the area of an irregular hexagon, we first have to organize it into rectangles and right triangles and then we have to find the area of each geometric shape. The procedure of finding the area of an irregular hexagon is no doubt longer and complex than finding the area of a regular triangle. To find the area of a regular hexagon, you just need to use the formula based on the information given 

Question 4: Calculate the area and perimeter of a given regular hexagon whose side is 4 cm. (2 marks)

Answer: Given parameters are,

Side of the hexagon, a = 4 cm

Thus, area of Hexagon will be,

A = (3√3)2×a2

= (3√3)2×42

= 24√3 sqcm.

The perimeter of the hexagon will be,

P=6×a

=6×4

= 24 cm

Explanation; The given sides of regular hexagon is ‘a’ & it is 4 cm; thus, the area is calculated as 243–√sqcm & perimeter is 24 cm.

Question 5: Perimeter of a regular hexagonal board is 48 cm. Compute the area of this board. (2 marks)

Answer: Given parameters are:

Perimeter, P = 48 cm

Also, formula for perimeter is,

P=6×a

Thus side, a = P/6 = 48 / 6

a = 8 cm

Now, Area of a Hexagon formula is:

A = 3(√3/2)a2

= 3(√3/2) × 82

= 166.28 sq.cm

So, area of hexagon will be 166.28 sq.cm

Explanation; the given perimeter of regular hexagon is denoted by ‘P’ is 48 cm. by this the sides of hexagon can be determined. It will be 8 cm. having sides can help in determining the AREA of the regular hexagon.

Question 6: Calculate the area of a regular hexagon whose side is 7 cm. (2 marks)

Answer: Area of a hexagon equation is A = (3√3)/2 x L2

Here, side l = 7 cm

Put the value L = 7 cm.

Area = 3 x (1.732/2) x 7 x 7

= 2.598 x 49

=127.302 cm2

Explanation; the sides of the regular hexagon is given as ‘a’ is equal to 7 cm. the area will be calculated by applying the formula & putting the value of sides.

Question 7: Calculate the perimeter and area of a regular hexagon having a side equal to 4 cm using regular hexagon formula. (2 marks)

Answer: To Find: Perimeter and area

given: s = 4cm

Using the regular hexagon formula for perimeter

Perimeter (P) = 6s

P = 6 × 4

P = 24 cm

Using the regular hexagon formula for area

Area of hexagon = (3√3 × s2)/2

= (3√3 × 42)/2

= 41.56 cm2

Explanation; the sides of regular hexagon ‘a’ is given i.e., 4 cm. thus putting the values in formula the Perimeter and area of the hexagon are 24 cm and 41.56 cm2.

Question 8: A hexagonal board has a perimeter equal to 12 cm. Find its area. (2 marks)

Answer: To Find: Area of the hexagon.

Given: Perimeter = 12 cm.

The perimeter of hexagon = 6s

12 = 6 a

a = 2cm

Using the regular hexagon formula for Area,

Area of hexagon = (3√3 × s2)/2

= (3√3 × 22)/2

=10.39 cm2

Explanation; the perimeter of the regular hexagon is given as ‘P’ is equal to 12 cm. by calculating the side from perimeter formula the area can be calculated. Thus, the area of the hexagonal board is 10.39 cm2.

Question 9: If the area of a regular hexagon is 24√3 cm2, find its perimeter. (2 marks)

Answer: Let the side of a regular hexagon be a.

Then, its area = (3√3)/2 × (Side)2

= (3√3)/2 × a2

Therefore, 24√3 cm2 = (3√3)/2 × a2

a2 = (48√3) / (3√3) cm2

a2 = 16

Therefore, a = 4 cm.

Therefore, perimeter = 6a = 6 × 4 cm = 24 cm.

Explanation; the area of the regular hexagon ‘A’ is given i.e., 24√3 cm2. The sides ‘a’ can be calculated by using the area formula, i.e., 4 cm. the side multiplies by 6 is the perimeter thus, the perimeter is 24 cm.

Question 10: Calculate the area and perimeter of a regular hexagon whose side is 4.1cm. (2 marks)

Answer: Given, side of the hexagon = 4.1 cm

Area of a Hexagon = 3(√3/2)a2

Area of a Hexagon = 3(√3/2) × (4.1)2= 43.67cm²

Perimeter of the hexagon = 6a = 6 × 4.1 = 24.6cm

Explanation; the side of the regular hexagon is given i.e., is 4.1 cm, the perimeter is calculated by multiplying it by 6 & the area will be calculated by applying the desired formula & outing the values. Thus, the area & perimeter will be 43.67cm² & 24.6cm.

Mathematics Related Links:

Class 8 Mathematics Chapter 1 Rational Numbers Class 8 Mathematics Chapter 2 Linear Equations in One Variable Class 8 Mathematics Chapter 4 Practical Geometry
Class 8 Mathematics Chapter 5 Data Handling Class 8 Mathematics Chapter 6 Squares and Square Roots Class 8 Mathematics Chapter 7 Cubes and Cube Roots
Class 8 Mathematics Chapter 8 Comparing Quantities Class 8 Mathematics Chapter 9 Algebraic Expressions and Identities Class 8 Mathematics Chapter 10 Visualising Solid Shapes
Class 8 Mathematics Chapter 11 Mensuration Class 8 Mathematics Chapter 12 Exponents and Powers Class 8 Mathematics Chapter 13 Direct and Inverse Proportions
Class 8 Mathematics Chapter 14 Factorisation Class 8 Mathematics Chapter 15 Introduction to Graphs   Class 8 Mathematics Chapter 16 Playing with Numbers 

CBSE X Related Questions

  • 1.
    The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.


      • 2.
        A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.


          • 3.
            Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

              • $\frac{5}{12}$
              • $\frac{5}{6}$
              • $1$
              • $0$

            • 4.
              Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.


                • 5.
                  In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.


                    • 6.
                      A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

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