NCERT Solutions for Class 9 Maths Chapter 10: Circles

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The NCERT Solutions for class 9 Maths Chapter 10 Circles have been provided in the article below. A circle is the collection of all the points in a plane where, each of which is at a constant distance from a fixed point in that particular plane. A circle refers to the path of a point which moves in a plane in such a way that it remains at a constant distance from a fixed point in a plane. 

Class 9 Maths Chapter 10 Circles belong to Unit 4 Geometry which has a weightage of 27 marks in the Class 9 Maths Examination. NCERT Solutions for Class 9 Maths for Chapter 10 cover the following important concepts: 

  1. Cyclic Quadrilateral
  2. Semi Circle
  3. Tangent to a Circle

Download: NCERT Solutions for Class 9 Mathematics Chapter 10 pdf


NCERT Solutions for Class 9 Mathematics Chapter 10

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Important Topics in Class 9 Maths Chapter 10 Circles

Important Topics in Class 9 Maths Chapter 10 Circles are given below:

Cyclic Quadrilateral

Cyclic quadrilaterals are a type of quadrilaterals that have four vertices lying on the circumference of the same circle. It is simply a quadrilateral circumscribed within a circle.

Example: State the Brahmagupta Theorem.

Solution: Brahmagupta theorem helps determine the area and perimeter of a cyclic quadrilateral.
Area, ‘K’, of a cyclic quadrilateral that has sides a, b, c, and d can be expressed by:
K = \(\sqrt{( s − a ) ( s − b ) ( s − c ) ( s − d) } \)
Now, the perimeter of the respective quadrilateral can be expressed as 2S. Thus, S is the semi perimeter which can be showed as,
S = (1/2) × (a + b + c + d)

Semi Circle

Geometrically, a semicircle is a plane two-dimensional shape which can be formed by dividing a circle into exactly two segments. 

Example: What is the area and perimeter of a semicircle?

Solution: The Area of a semicircle is = 1/2 (π r2)
The Perimeter of a semicircle is = (1/2) πd + d

Tangent to a Circle

A tangent to a circle is a line that touches the curved line or surface at a single point in geometry. A tangent to a circle can be expressed as a line that intersects the circle at a single point.

Example: List three properties of a Tangent.

Solution: The properties of a Tangent are:

  • The tangent is known to make a single point contact with the respective circle.
  • When the tangency occurs, it remains perpendicular to the circle's radius.
  • The tangent can never have two points intersecting the circle.

NCERT Solutions for Class 9 Maths Chapter 10 Exercises:

The detailed solutions for all the NCERT Solutions for Circles under different exercises are:

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CBSE X Related Questions

  • 1.
    Assertion (A) : The system of linear equations $3x - 5y + 7 = 0$ and $-6x + 10y + 14 = 0$ is inconsistent.
    Reason (R) : When two linear equations don't have unique solution, they always represent parallel lines.

      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Assertion (A) is false, but Reason (R) is true.

    • 2.
      A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.


        • 3.
          In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.


            • 4.
              Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

                • $\frac{5}{12}$
                • $\frac{5}{6}$
                • $1$
                • $0$

              • 5.
                An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

                  • $50^\circ$
                  • $60^\circ$
                  • $45^\circ$
                  • $30^\circ$

                • 6.
                  In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

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