NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Solutions are based on two theorems, (i) The perpendicular from the center of a circle to a chord is seen to bisect the chord. (ii) The line drawn through the center of a circle to bisect a chord is seen to be perpendicular to it.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 10 Exercise 10.3 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 10 Exercise 10.3 Solutions

Exercise Solutions of Class 9 Maths Chapter 10 Circles

Also check other Exercise Solutions of Class 9 Maths Chapter 10 Circles

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Important Chapter Related Topics
Cyclic quadrilateral	Semi Circle	Tangent circle formula
Circles Important Question	Circles Revision Notes	Tangent to a Circle

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CBSE X Related Questions

1.
If the zeroes of the polynomial $p(x) = 2x^2 - 7x + 6$ are $\alpha$ and $\beta$, then the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
- $\frac{7}{2}$
- $\frac{6}{7}$
- $\frac{-7}{6}$
- $\frac{7}{6}$
View Solution
2.
It is given that $\triangle ABC \sim \triangle EDF$. Which of the following is not true?
- $\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}$
- $\frac{AB}{ED} = \frac{AC}{EF}$
- $\angle A = \angle D, \angle C = \angle F$
- $\frac{AB + BC}{AC} = \frac{ED + DF}{EF}$
View Solution
3.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is
- $55^\circ$
- $20^\circ$
- $35^\circ$
- $70^\circ$
View Solution
4.
For an acute angle $\theta$, if $\sin \theta = \frac{1}{9}$, then value of $\frac{9 \csc \theta + 1}{9 \csc \theta - 1}$ is
- $0$
- $\frac{80}{81}$
- $1$
- $\frac{82}{80}$
View Solution
5.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
6.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is
- 34
- 43
- 38.5
- 41.5
View Solution

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NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Solutions

Exercise Solutions of Class 9 Maths Chapter 10 Circles

CBSE X Related Questions

1.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

2.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

3.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

4.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

5.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

6.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

Similar Mathematics Concepts

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NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Solutions

Exercise Solutions of Class 9 Maths Chapter 10 Circles

CBSE X Related Questions

1.If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

2.It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

3.In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

4.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

5.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

6.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

2.
It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

3.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

4.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

5.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

6.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is