NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.3 Solutions are based on two theorems, (i) The perpendicular from the center of a circle to a chord is seen to bisect the chord. (ii) The line drawn through the center of a circle to bisect a chord is seen to be perpendicular to it.

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Check out NCERT Solutions for Class 9 Maths Chapter 10 Exercise 10.3 Solutions

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Exercise Solutions of Class 9 Maths Chapter 10 Circles

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CBSE X Related Questions

  • 1.
    Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.


      • 2.
        In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.


          • 3.
            The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.


              • 4.
                Assertion (A) : The system of linear equations $3x - 5y + 7 = 0$ and $-6x + 10y + 14 = 0$ is inconsistent.
                Reason (R) : When two linear equations don't have unique solution, they always represent parallel lines.

                  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                  • Assertion (A) is true, but Reason (R) is false.
                  • Assertion (A) is false, but Reason (R) is true.

                • 5.
                  If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

                    • $x^2 + 5x - 4$
                    • $(x + 3) (-x + 8)$
                    • $a(x^2 + 5x - 24)$
                    • $x^2 - 24$

                  • 6.
                    PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

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