NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 10 Circles Exercise 10.2 Solutions are based on two theorems, which are, (i) Equal circle chords subtend equal angles at the center. (ii) If the angles subtended by the chords at the center tend to be equal, then the chords are equal too.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 10 Exercise 10.2 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 10 Exercise 10.2 Solutions

Read More: NCERT Solutions For Class 9 Maths Chapter 10 Circles

Exercise Solutions of Class 9 Maths Chapter 10 Circles

Also check other Exercise Solutions of Class 9 Maths Chapter 10 Circles

Also Check:

Important Chapter Related Topics
Cyclic quadrilateral	Semi Circle	Tangent circle formula
Circles Important Question	Circles Revision Notes	Tangent to a Circle

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CBSE X Related Questions

1.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then
- \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
View Solution
2.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
3.
Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
View Solution
4.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
View Solution
5.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
6.
Prove that :
\(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).
View Solution

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