NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.2 Solutions

Content Curator

NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclid's Geometry Exercise 5.2 Solutions are based on Euclid’s fifth postulate.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.2 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

Also check other Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

NCERT Solutions for Class 9 Maths Chapter 5 Introduction to Euclid's Geometry Exercise 5.1 Solutions

Also Check:

Chapter Related Topics
Introduction to Euclid’s Geometry - MCQs	Euclid’s Division Lemma

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
If the zeroes of the polynomial $p(x) = 2x^2 - 7x + 6$ are $\alpha$ and $\beta$, then the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
- $\frac{7}{2}$
- $\frac{6}{7}$
- $\frac{-7}{6}$
- $\frac{7}{6}$
View Solution
2.
For an acute angle $\theta$, if $\sin \theta = \frac{1}{9}$, then value of $\frac{9 \csc \theta + 1}{9 \csc \theta - 1}$ is
- $0$
- $\frac{80}{81}$
- $1$
- $\frac{82}{80}$
View Solution
3.
Assertion (A) : H.C.F. $(36 m^{2}, 18 m) = 18 m$, where $m$ is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
4.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is
- 34
- 43
- 38.5
- 41.5
View Solution
5.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is
- $6$
- $4$
- $\pm 4$
- $3$
View Solution
6.
Which of the following graphs represents a polynomial with both zeroes being positive?
View Solution

View All

Similar Mathematics Concepts

NCERT Solutions for Class 9 Maths Chapter 5: Introduction to Euclid’s Geometry

Introduction to Euclid's Geometry: Facts, Axioms and Postulates

Class-9 Maths: Chapter 5, Introduction to Euclid’s Geometry - MCQs

Introduction to Euclid's Geometry Important Questions

NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.1 Solutions

Mathematics Preparation Guides

Statistics: Mean, Median, Variance and Cumulative Frequency Curve

Remainder Theorem: Definition, Steps & Examples

Angle Formula: Definition, Different Types, Solved Example

Trapezoids: Isosceles, Scalene Properties, Area, Properties, Examples

Quadrilateral Angle Sum Property: Theorem, Types & Example

Frequency Polygons: Steps, Formula & Examples

Area of Parallelogram: How to Calculate Area of Parallelogram?

Congruence of Triangles: SSS, SAS, ASA & RHS Rules

Quadrilateral Formulas: Types and Properties

Properties of Triangle: Types, Formulas & Examples

Class 9 Maths MCQ: Chapter-wise with Solutions

Properties of Parallel Lines: Transitive & Symmetric Properties

Isosceles triangle: Types, Properties, Angles & Examples

Operations on Rational Numbers:Rules, Properties & Examples

Addition and Subtraction of Integers: Rules & Examples

Scalene Triangle: Types, Formulas, Properties & Examples

Quadrant: Types, Sign Convention & Examples

Rationalize the Denominator: Explanation and Solved Examples

Area of a Kite: Formula, Derivation & Examples

Volume of a Pyramid: Formula and Solved Example

Mathematics NCERT Solutions

Linear Equation in Two Variables: Graph, Elimination and Substitution

Types of Triangles: Important Terms, Scalene, Acute, and Obtuse Triangle

Formula Of Perimeter Shapes

Sphere Formula: Diameter, Surface Area and Volume

Ordinate: Abscissa, Plotting Ordinates, Relation, Solved Examples

Integers as Exponents: Explanation, Rules and Method of Solving

Central Tendency: Definition, Methods and Sample Questions

Line Segment: Definition, Measurement and Examples

Line, Line Segment and Ray: Differentiation and Sample Questions

Area of Equilateral Triangle, Perimeter & Altitude Formulas

You can also check

NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

CBSE X Related Questions

1.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

4.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

5.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

6.
Which of the following graphs represents a polynomial with both zeroes being positive?

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions for Class 9 Maths Chapter 5 Exercise 5.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 5 Introduction to Euclid's Geometry

CBSE X Related Questions

1.If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

2.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number. Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

4.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

5.In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

6.Which of the following graphs represents a polynomial with both zeroes being positive?

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

2.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

3.
Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

4.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

5.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

6.
Which of the following graphs represents a polynomial with both zeroes being positive?