NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.1 Solutions are based on the introduction of the topic.

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Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles 

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CBSE X Related Questions

  • 1.
    A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


      • 2.
        In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

          • \(2.5\) cm
          • \(10.5\) cm
          • \(3.5\) cm
          • \(\frac{14}{3}\) cm

        • 3.
          D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


            • 4.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

              • 5.
                In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

                  • \( 130^\circ \)
                  • \( 50^\circ \)
                  • \( 120^\circ \)
                  • \( 90^\circ \)

                • 6.
                  If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                    • \(4 \text{ cm}\)
                    • \(4\sqrt{2} \text{ cm}\)
                    • \(8 \text{ cm}\)
                    • \(2\sqrt{2} \text{ cm}\)

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