NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.4 Solutions are based on parallelograms and triangles that have the same base and same parallel lines. It also covers the median of a triangle that divides into two triangles of equal areas.

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Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles 

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CBSE X Related Questions

  • 1.
    The HCF of 960 and 432 is :

      • 48
      • 54
      • 72
      • 36

    • 2.
      In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

        • \( 130^\circ \)
        • \( 50^\circ \)
        • \( 120^\circ \)
        • \( 90^\circ \)

      • 3.
        PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


          • 4.
            If \( \alpha, \beta \) are the zeroes of the quadratic polynomial \( px^2 + qx + r \), then find the value of \( \alpha^3\beta + \beta^3\alpha \).


              • 5.
                In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

                  • \(2.5\) cm
                  • \(10.5\) cm
                  • \(3.5\) cm
                  • \(\frac{14}{3}\) cm

                • 6.
                  If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

                    • \(4 \text{ cm}\)
                    • \(4\sqrt{2} \text{ cm}\)
                    • \(8 \text{ cm}\)
                    • \(2\sqrt{2} \text{ cm}\)

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