NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.4 Solutions are based on parallelograms and triangles that have the same base and same parallel lines. It also covers the median of a triangle that divides into two triangles of equal areas.

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CBSE X Related Questions

  • 1.
    For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

      • \(0\)
      • \(\frac{80}{81}\)
      • \(1\)
      • \(\frac{82}{80}\)

    • 2.
      If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

        • \( -\frac{2}{3} \)
        • \( \frac{2}{3} \)
        • \( \frac{1}{3} \)
        • \( -\frac{1}{3} \)

      • 3.
        In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

          • $6$
          • $4$
          • $\pm 4$
          • $3$

        • 4.
          It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

            • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
            • \(\frac{AB}{ED} = \frac{AC}{EF}\)
            • \(\angle A = \angle D, \angle C = \angle F\)
            • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

          • 5.
            Arc \(PQ\) subtends an angle \(\theta\) at the centre of the circle with radius \(6.3 \text{ cm}\). If \(\text{Arc } PQ = 11 \text{ cm}\), then the value of \(\theta\) is

              • \(10^{\circ}\)
              • \(60^{\circ}\)
              • \(45^{\circ}\)
              • \(100^{\circ}\)

            • 6.
              Which of the following graphs represents a polynomial with both zeroes being positive?

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