NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.2 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.2 Solutions are based on parallelograms with the same base and parallel lines.

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Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles 

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CBSE X Related Questions

  • 1.
    \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

      • \(\frac{21}{4} \text{ cm}\)
      • \(\frac{28}{3} \text{ cm}\)
      • \(\frac{12}{7} \text{ cm}\)
      • \(5.5 \text{ cm}\)

    • 2.
      PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


        • 3.
          The natural number 1 is :

            • a prime number.
            • a composite number.
            • prime as well as composite.
            • neither prime nor composite.

          • 4.
            If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

              • $x^2 + 5x - 4$
              • $(x + 3) (-x + 8)$
              • $a(x^2 + 5x - 24)$
              • $x^2 - 24$

            • 5.
              The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

                • 0
                • 1
                • 3
                • 2

              • 6.
                The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

                  • $q - 9p$
                  • $p - 9q$
                  • $p + 9q$
                  • $2p + 9q$

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