NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.2 Solutions

Content Curator

NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.2 Solutions are based on parallelograms with the same base and parallel lines.

Download PDF: NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.2 Solutions

Check out NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

Also check other Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

Also Check:

Important Chapter Related Topics
Area of Triangle	Perimeter of a Parallelogram
Area of a Trapezoid Formula	Trapezoids

Also check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
If $ \alpha $ and $ \beta $ are two zeroes of a polynomial $ f(x) = px^2 - 2x + 3p $ and $ \alpha + \beta = \alpha\beta $, then value of p is :
- $ -\frac{2}{3} $
- $ \frac{2}{3} $
- $ \frac{1}{3} $
- $ -\frac{1}{3} $
View Solution
2.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is
- $6$
- $4$
- $\pm 4$
- $3$
View Solution
3.
If roots of the quadratic equation $x^2 - k\sqrt{3}x + 2 = 0$ are real and equal, then value of k is
- $-2$
- $\sqrt{\frac{8}{3}}$
- $1$
- $2$
View Solution
4.
For an acute angle $\theta$, if $\sin \theta = \frac{1}{9}$, then value of $\frac{9 \csc \theta + 1}{9 \csc \theta - 1}$ is
- $0$
- $\frac{80}{81}$
- $1$
- $\frac{82}{80}$
View Solution
5.
The value of k for which sum of the zeroes of the polynomial $p(x) = 3x^2 - kx + 6$ is 2, is
- 2
- $-6$
- $-2$
- 6
View Solution
6.
If the zeroes of the polynomial $p(x) = 2x^2 - 7x + 6$ are $\alpha$ and $\beta$, then the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
- $\frac{7}{2}$
- $\frac{6}{7}$
- $\frac{-7}{6}$
- $\frac{7}{6}$
View Solution

View All

Similar Mathematics Concepts

Trapezoids: Isosceles, Scalene Properties, Area, Properties, Examples

Area of Parallelogram: How to Calculate Area of Parallelogram?

Area of Parallelogram and Triangles: Important Theorems

NCERT Solutions for Class 9 Maths Chapter 9: Areas of parallelograms and triangles

MCQs for Areas Of Parallelogram Triangles: Chapter 9

Important Questions for CBSE Class 9: Area of Parallelograms and Triangles

NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.1 Solutions

NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.3 Solutions

NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

Mathematics Preparation Guides

Statistics: Mean, Median, Variance and Cumulative Frequency Curve

Remainder Theorem: Definition, Steps & Examples

Angle Formula: Definition, Different Types, Solved Example

Trapezoids: Isosceles, Scalene Properties, Area, Properties, Examples

Quadrilateral Angle Sum Property: Theorem, Types & Example

Frequency Polygons: Steps, Formula & Examples

Area of Parallelogram: How to Calculate Area of Parallelogram?

Congruence of Triangles: SSS, SAS, ASA & RHS Rules

Quadrilateral Formulas: Types and Properties

Properties of Triangle: Types, Formulas & Examples

Class 9 Maths MCQ: Chapter-wise with Solutions

Properties of Parallel Lines: Transitive & Symmetric Properties

Isosceles triangle: Types, Properties, Angles & Examples

Operations on Rational Numbers:Rules, Properties & Examples

Addition and Subtraction of Integers: Rules & Examples

Scalene Triangle: Types, Formulas, Properties & Examples

Quadrant: Types, Sign Convention & Examples

Rationalize the Denominator: Explanation and Solved Examples

Area of a Kite: Formula, Derivation & Examples

Volume of a Pyramid: Formula and Solved Example

Mathematics NCERT Solutions

Linear Equation in Two Variables: Graph, Elimination and Substitution

Types of Triangles: Important Terms, Scalene, Acute, and Obtuse Triangle

Formula Of Perimeter Shapes

Sphere Formula: Diameter, Surface Area and Volume

Ordinate: Abscissa, Plotting Ordinates, Relation, Solved Examples

Integers as Exponents: Explanation, Rules and Method of Solving

Central Tendency: Definition, Methods and Sample Questions

Line Segment: Definition, Measurement and Examples

Line, Line Segment and Ray: Differentiation and Sample Questions

Area of Equilateral Triangle, Perimeter & Altitude Formulas

NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

CBSE X Related Questions

1.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

2.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

3.
If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

4.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

5.
The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

6.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.2 Solutions

Exercise Solutions of Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles

CBSE X Related Questions

1.If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

2.In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

3.If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

4.For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

5.The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

6.If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

2.
In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

3.
If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

4.
For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

5.
The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

6.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is