NCERT Solutions for Class 9 Maths Chapter 9 Exercise 9.4 Solutions

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NCERT Solutions for Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.4 Solutions are based on parallelograms and triangles that have the same base and same parallel lines. It also covers the median of a triangle that divides into two triangles of equal areas.

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CBSE X Related Questions

  • 1.
    There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

      • 144
      • 2
      • 420
      • 272

    • 2.
      The graph of a quadratic polynomial f(x) passes through (5,0), (0, -1) and (-2, 0). The two factors of the polynomial are

        • \((x + 2), (x - 5)\)
        • \((x + 5), (x - 2)\)
        • \((x + 1), (x - 5)\)
        • \((x - 1), (x + 2)\)

      • 3.
        For an acute angle \(\theta\), if \(\sin \theta = \frac{1}{9}\), then value of \(\frac{9 \csc \theta + 1}{9 \csc \theta - 1}\) is

          • \(0\)
          • \(\frac{80}{81}\)
          • \(1\)
          • \(\frac{82}{80}\)

        • 4.
          The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

            • 2
            • \(-6\)
            • \(-2\)
            • 6

          • 5.
            In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

              • $6$
              • $4$
              • $\pm 4$
              • $3$

            • 6.
              If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

                • \( -\frac{2}{3} \)
                • \( \frac{2}{3} \)
                • \( \frac{1}{3} \)
                • \( -\frac{1}{3} \)

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