Perpendicular Bisector: Definition, Properties and Construction

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Namrata Das

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A perpendicular bisector is a line or a line segment that intersects with another line or line segment perpendicularly and divides that line into two parts of equal measurement. A perpendicular bisector can be drawn by using a ruler, a compass and a pencil. Similarly, two lines are said to be perpendicular to each other when they intersect each other at 90 degrees. And, a bisector is a line that divides another line into two equal parts. Thus, a perpendicular bisector of a given line segment BC implies that it intersects BC at a right angle and cuts the line segment into two equal parts.

Key Takeaways: Perpendicular Bisector, line segment, arcs, right angle, Perpendicular Bisector of a Triangle, Points of intersection, circumcenter


What is a Perpendicular Bisector?

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A perpendicular bisector can be defined as a line segment that bisects another line segment at 90 degrees or at a right angle, through the intersection point. Thus, we can say that a perpendicular bisector always divides a line segment into two equal halves through its midpoint as the term bisect itself means dividing equally.


Construction of a Perpendicular Bisector

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To construct a perpendicular bisector, one will require a ruler, a compass and a pencil. There are certain steps that need to be followed to construct a perpendicular bisector of a given line segment. The steps are mentioned below:

  • Step 1: Draw a line segment, suppose XY of any length.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of the length of XY.
  • Step 3: Place the compass pointer at point X and draw arcs above and below the line segment.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point Y and draw arcs above and below the line segment.
  • Step 5: Mark the points of intersection as `P’ and `Q’.
  • Step 6: Using a ruler, join the points `P’ and `Q’.

The perpendicular bisector bisects XY at a point `O’. Thus, the length of XO is equal to OY and the angle between the two line segments is 90 degree.

Also Read: Introduction to Constructions


Perpendicular Bisector of a Triangle

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The perpendicular bisector of a triangle can be defined as a line segment that bisects the sides of a triangle and is perpendicular to the sides. It is necessary that the line segment should pass through the midpoint of the sides of a triangle. There can be a total of three perpendicular bisectors for a triangle (one for each side). The point at which all the three perpendicular bisectors of a triangle meet is called the circumcenter of a triangle.

Perpendicular Bisector of a Triangle

Perpendicular Bisector of a Triangle


Properties of a Perpendicular Bisector

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  • It divides a line or a line segment into two equal halves.
  • It makes a right angle with the line that is being bisected.
  • They divide the line segment through its midpoint.
  • Every point in the perpendicular bisector is equidistant from the given points.
  • It divides the sides of a triangle into equal parts.
  • The point of intersection of the perpendicular bisectors in a triangle is called the circumcenter of a triangle.

Applications of a Perpendicular Bisector

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Perpendicular bisectors are often used in geometry to proof theorems and do constructions.

  • Perpendicular bisectors are used to construct an isosceles triangle.
  • They are also used to find the circumcenter of a triangle.

Points to Remember

  • A perpendicular bisector is a line that bisects another given line segment at a right angle and divides that line into two equal parts through the intersection point.
  • Perpendicular bisector on a line segment can be constructed easily by using a ruler, a compass and a pencil.
  • The perpendicular bisector of a triangle can be defined as a line segment that bisects the sides of a triangle and is perpendicular to the sides.
  • There can be a total of three perpendicular bisectors for a triangle (one for each side of a triangle).
  • The intersection point at which all the three perpendicular bisectors of a triangle meet is called the circumcenter of a triangle.

Sample Questions 

Ques: Draw a line segment of given length 6.6cm. Draw the perpendicular bisector and measure the length of each part. [4 Marks]

Ans: The steps for construction are mentioned below as follows:

  • Step 1: Draw a line segment AB of given length = 6.6cm.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of the length of AB.
  • Step 3: Place the compass pointer at point A and draw arcs above and below the line segment.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point B and draw arcs above and below the line segment.
  • Step 5: Mark the points of intersection as `E’ and `F’.
  • Step 6: Using a ruler, join the points `E’ and `F’.

The perpendicular bisector bisects AB at a point `M’. Thus, the length of AM is equal to MB. Therefore, AM = MB = 3.3cm

Ques: Draw a triangle ABC with given measurements as BC = 3.2 cm, AB = 3.6 cm and ∠ =1200. [4 Marks]

Ans: The steps for construction with the figure of the required triangle are shown below as follows:

  • Step 1: Draw ∠XBY which measures 1200.
  • Step 2: Now, from ray BX, cut off the line segment BC which is of length 3.2 cm.
  • Step 3: Then, from ray BY, cut off the line segment BA which is of length 3.6 cm.
  • Step 4: Now, join CA to obtain the required triangle.

Ques: State the Perpendicular Bisector Theorem. [2 Marks]

Ans: The perpendicular bisector theorem states that any point on the perpendicular bisector is equidistant from both the endpoints of the line segment on which it is drawn.

Ques: What is the point called at which all the three perpendicular bisectors of a triangle meet? [1 Mark]

Ans: The point at which all the three perpendicular bisectors of a triangle meet is called the circumcenter of a triangle.

Ques: Where do the points of intersection of all the perpendicular bisectors for different types of triangles meet? [2 Marks]

Ans: In an acute triangle, the points of intersection meet inside a triangle. In an obtuse angled triangle, the points of intersection meet outside a triangle and in right triangles; the points of intersection meet at the hypotenuse.

Ques: Write the steps of how to construct a perpendicular bisector of a triangle. [5 Marks]

Ans: The steps to construct a perpendicular bisector of a triangle are mentioned below as follows:

  • Step 1: Draw a triangle with the help of a ruler and mark the vertices as A, B, and C.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of BC as radius.
  • Step 3: Place the compass pointer at point B and draw arcs above and below the line segment.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point C and draw arcs above and below the line segment without changing the radius.
  • Step 5: Mark the points of intersection as `X’ and `Y’.
  • Step 6: Using a ruler, join the points `X’ and `Y’.

This is the perpendicular bisector for one side of the triangle, i.e., BC.

  • Step 7: Now, repeat the same from step 2 to step 6 for sides AB and AC. All the three perpendicular bisectors drawn are seen to make an angle of 900 at the midpoint of each side.

Ques: Proof that the points of intersection of all the perpendicular bisectors for an obtuse angle triangle PQR with measurements given as follows; PQ = 5 units, QR = 8 units, and PR = 9 units lies outside the triangle? [5 Marks]

Ans: Before doing the construction, we know that in a triangle, there are a total of three perpendicular bisectors that can be drawn from each side of a triangle. Also, that the perpendicular bisector of any triangle bisects the sides at its midpoint.

The steps to find the perpendicular bisectors of a triangle with the given measurements are shown below as follows:

  • Step 1: Draw a line segment PQ of given length = 5 units.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of the length of PQ.
  • Step 3: Place the compass pointer at point P and draw arcs above and below the line segment PQ.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point Q and draw arcs above and below the line segment.
  • Step 5: Join the points of intersection with the help of a ruler.
  • Step 6: Now, repeat the same from step 2 to step 5 and draw perpendicular bisectors for the sides QR and PR..

Ques: The diameter of a circle whose radius is given 4 units. Draw a perpendicular bisector. [5 Marks]

Ans: Given,

Radius of a circle = 4 units

Diameter = 2 × radius

= 2 × 4

= 8 units

The steps to construct a perpendicular bisector on a diameter of a circle are shown below as follows:

  • Step 1: Draw a line segment XY of length = 8 units.
  • Step 2: Take a compass and then adjust it with a length of a little more than 4 units.
  • Step 3: Place the compass pointer at point X and draw arcs above and below the line segment XY.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point Y and draw arcs above and below the line segment.
  • Step 5: Mark the points of intersection as `P’ and `Q’.
  • Step 6: Using a ruler, join the points `P’ and `Q’.

The line PQ is the perpendicular bisector for the diameter of the circle.

  • Step 7: Mark the point of intersection as `O’.

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CBSE X Related Questions

  • 1.
    The value of \(p\) for which roots of the quadratic equation \(x^{2} - px + 6 = 0\) are rational, is

      • \(1\)
      • \(-5\)
      • \(25\)
      • \(\sqrt{5}\)

    • 2.
      The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

        • 0
        • 1
        • 3
        • 2

      • 3.
        There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

          • 144
          • 2
          • 420
          • 272

        • 4.
          A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is \(3/5\), then find the number of yellow balls.


            • 5.
              D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


                • 6.
                  The HCF of 960 and 432 is :

                    • 48
                    • 54
                    • 72
                    • 36

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