Perpendicular Bisector: Definition, Properties and Construction

Namrata Das logo

Namrata Das

Exams Prep Master

A perpendicular bisector is a line or a line segment that intersects with another line or line segment perpendicularly and divides that line into two parts of equal measurement. A perpendicular bisector can be drawn by using a ruler, a compass and a pencil. Similarly, two lines are said to be perpendicular to each other when they intersect each other at 90 degrees. And, a bisector is a line that divides another line into two equal parts. Thus, a perpendicular bisector of a given line segment BC implies that it intersects BC at a right angle and cuts the line segment into two equal parts.

Key Takeaways: Perpendicular Bisector, line segment, arcs, right angle, Perpendicular Bisector of a Triangle, Points of intersection, circumcenter


What is a Perpendicular Bisector?

[Click Here for Sample Questions]

A perpendicular bisector can be defined as a line segment that bisects another line segment at 90 degrees or at a right angle, through the intersection point. Thus, we can say that a perpendicular bisector always divides a line segment into two equal halves through its midpoint as the term bisect itself means dividing equally.


Construction of a Perpendicular Bisector

[Click Here for Sample Questions]

To construct a perpendicular bisector, one will require a ruler, a compass and a pencil. There are certain steps that need to be followed to construct a perpendicular bisector of a given line segment. The steps are mentioned below:

  • Step 1: Draw a line segment, suppose XY of any length.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of the length of XY.
  • Step 3: Place the compass pointer at point X and draw arcs above and below the line segment.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point Y and draw arcs above and below the line segment.
  • Step 5: Mark the points of intersection as `P’ and `Q’.
  • Step 6: Using a ruler, join the points `P’ and `Q’.

The perpendicular bisector bisects XY at a point `O’. Thus, the length of XO is equal to OY and the angle between the two line segments is 90 degree.

Also Read: Introduction to Constructions


Perpendicular Bisector of a Triangle

[Click Here for Sample Questions]

The perpendicular bisector of a triangle can be defined as a line segment that bisects the sides of a triangle and is perpendicular to the sides. It is necessary that the line segment should pass through the midpoint of the sides of a triangle. There can be a total of three perpendicular bisectors for a triangle (one for each side). The point at which all the three perpendicular bisectors of a triangle meet is called the circumcenter of a triangle.

Perpendicular Bisector of a Triangle

Perpendicular Bisector of a Triangle


Properties of a Perpendicular Bisector

[Click Here for Sample Questions]

  • It divides a line or a line segment into two equal halves.
  • It makes a right angle with the line that is being bisected.
  • They divide the line segment through its midpoint.
  • Every point in the perpendicular bisector is equidistant from the given points.
  • It divides the sides of a triangle into equal parts.
  • The point of intersection of the perpendicular bisectors in a triangle is called the circumcenter of a triangle.

Applications of a Perpendicular Bisector

[Click Here for Sample Questions]

Perpendicular bisectors are often used in geometry to proof theorems and do constructions.

  • Perpendicular bisectors are used to construct an isosceles triangle.
  • They are also used to find the circumcenter of a triangle.

Points to Remember

  • A perpendicular bisector is a line that bisects another given line segment at a right angle and divides that line into two equal parts through the intersection point.
  • Perpendicular bisector on a line segment can be constructed easily by using a ruler, a compass and a pencil.
  • The perpendicular bisector of a triangle can be defined as a line segment that bisects the sides of a triangle and is perpendicular to the sides.
  • There can be a total of three perpendicular bisectors for a triangle (one for each side of a triangle).
  • The intersection point at which all the three perpendicular bisectors of a triangle meet is called the circumcenter of a triangle.

Sample Questions 

Ques: Draw a line segment of given length 6.6cm. Draw the perpendicular bisector and measure the length of each part. [4 Marks]

Ans: The steps for construction are mentioned below as follows:

  • Step 1: Draw a line segment AB of given length = 6.6cm.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of the length of AB.
  • Step 3: Place the compass pointer at point A and draw arcs above and below the line segment.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point B and draw arcs above and below the line segment.
  • Step 5: Mark the points of intersection as `E’ and `F’.
  • Step 6: Using a ruler, join the points `E’ and `F’.

The perpendicular bisector bisects AB at a point `M’. Thus, the length of AM is equal to MB. Therefore, AM = MB = 3.3cm

Ques: Draw a triangle ABC with given measurements as BC = 3.2 cm, AB = 3.6 cm and ∠ =1200. [4 Marks]

Ans: The steps for construction with the figure of the required triangle are shown below as follows:

  • Step 1: Draw ∠XBY which measures 1200.
  • Step 2: Now, from ray BX, cut off the line segment BC which is of length 3.2 cm.
  • Step 3: Then, from ray BY, cut off the line segment BA which is of length 3.6 cm.
  • Step 4: Now, join CA to obtain the required triangle.

Ques: State the Perpendicular Bisector Theorem. [2 Marks]

Ans: The perpendicular bisector theorem states that any point on the perpendicular bisector is equidistant from both the endpoints of the line segment on which it is drawn.

Ques: What is the point called at which all the three perpendicular bisectors of a triangle meet? [1 Mark]

Ans: The point at which all the three perpendicular bisectors of a triangle meet is called the circumcenter of a triangle.

Ques: Where do the points of intersection of all the perpendicular bisectors for different types of triangles meet? [2 Marks]

Ans: In an acute triangle, the points of intersection meet inside a triangle. In an obtuse angled triangle, the points of intersection meet outside a triangle and in right triangles; the points of intersection meet at the hypotenuse.

Ques: Write the steps of how to construct a perpendicular bisector of a triangle. [5 Marks]

Ans: The steps to construct a perpendicular bisector of a triangle are mentioned below as follows:

  • Step 1: Draw a triangle with the help of a ruler and mark the vertices as A, B, and C.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of BC as radius.
  • Step 3: Place the compass pointer at point B and draw arcs above and below the line segment.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point C and draw arcs above and below the line segment without changing the radius.
  • Step 5: Mark the points of intersection as `X’ and `Y’.
  • Step 6: Using a ruler, join the points `X’ and `Y’.

This is the perpendicular bisector for one side of the triangle, i.e., BC.

  • Step 7: Now, repeat the same from step 2 to step 6 for sides AB and AC. All the three perpendicular bisectors drawn are seen to make an angle of 900 at the midpoint of each side.

Ques: Proof that the points of intersection of all the perpendicular bisectors for an obtuse angle triangle PQR with measurements given as follows; PQ = 5 units, QR = 8 units, and PR = 9 units lies outside the triangle? [5 Marks]

Ans: Before doing the construction, we know that in a triangle, there are a total of three perpendicular bisectors that can be drawn from each side of a triangle. Also, that the perpendicular bisector of any triangle bisects the sides at its midpoint.

The steps to find the perpendicular bisectors of a triangle with the given measurements are shown below as follows:

  • Step 1: Draw a line segment PQ of given length = 5 units.
  • Step 2: Take a compass and then adjust it with a length of a little more than half of the length of PQ.
  • Step 3: Place the compass pointer at point P and draw arcs above and below the line segment PQ.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point Q and draw arcs above and below the line segment.
  • Step 5: Join the points of intersection with the help of a ruler.
  • Step 6: Now, repeat the same from step 2 to step 5 and draw perpendicular bisectors for the sides QR and PR..

Ques: The diameter of a circle whose radius is given 4 units. Draw a perpendicular bisector. [5 Marks]

Ans: Given,

Radius of a circle = 4 units

Diameter = 2 × radius

= 2 × 4

= 8 units

The steps to construct a perpendicular bisector on a diameter of a circle are shown below as follows:

  • Step 1: Draw a line segment XY of length = 8 units.
  • Step 2: Take a compass and then adjust it with a length of a little more than 4 units.
  • Step 3: Place the compass pointer at point X and draw arcs above and below the line segment XY.
  • Step 4: Repeat step 2 and 3 by placing the compass pointer now at point Y and draw arcs above and below the line segment.
  • Step 5: Mark the points of intersection as `P’ and `Q’.
  • Step 6: Using a ruler, join the points `P’ and `Q’.

The line PQ is the perpendicular bisector for the diameter of the circle.

  • Step 7: Mark the point of intersection as `O’.

Check-Out:

CBSE X Related Questions

  • 1.
    Two dice are rolled together. The probability of getting an outcome $(x, y)$ where $x \gt y$, is

      • $\frac{5}{12}$
      • $\frac{5}{6}$
      • $1$
      • $0$

    • 2.
      In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.


        • 3.
          Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.


            • 4.
              An arc of length $2.2\text{ cm}$ subtends an angle $\theta$ at the centre of the circle with radius $2.8\text{ cm}$. The value of $\theta$ is

                • $50^\circ$
                • $60^\circ$
                • $45^\circ$
                • $30^\circ$

              • 5.
                In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.


                  • 6.
                    The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

                      • $1$
                      • $-5$
                      • $25$
                      • $\sqrt{5}$

                    Comments


                    No Comments To Show